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hjlf
3 years ago
14

What else would need to be congruent to show that abc = def by aas

Mathematics
2 answers:
sashaice [31]3 years ago
5 0

Answer:

The correct option is option A

Step-by-step explanation:

Given two triangles in which ∠B=∠E=50° and AB=DE=10 units.

we have to find the missing condition need to show the two triangles ABC and DEF congruent by AAS.

The condition given are

∠B=∠E

AB=DE

One side and one angle congruent given we need one more angle of both the triangles congruent such that the side does not lies between the two angles.

Hence, the possible angles are ∠C and ∠F.

The correct option is option A

PSYCHO15rus [73]3 years ago
5 0
The AAS or Angle-Angle-Side Postulate states that if you have two pairs of congruent angles and one pair of congruent sides, and the congruent side isn't between the two congruent angles, the two triangles are congruent.

Based on this, angle C must be congruent to angle F for these two triangles to be congruent by AAS. So your answer is A.
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BabaBlast [244]
Katie is 6; Cathy is 18!

X- Katie’s age now and 3x -Cathys age now
In 6 years, Katie is 12 and Cathy is 24.

2 x (X+6) = 3x + 6
2x + 12 = 3x + 6
6 = x
6 0
3 years ago
How many times can 8 go in to 1220
weeeeeb [17]
1220/8= 152.5
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5 0
3 years ago
Solve for a: b − 2a = c
vlada-n [284]

Answer:

a=-\frac{c-b}{2}

Step-by-step explanation:

Solving for the variable a, given that :

b-2a=c

We can first start start by subtracting b from both sides of the equation:

-2a=c-b

Now, we can divide both sides of the equation by the coefficient of a, which would be -2:

a=\frac{c}{-2}-\frac{b}{-2}

Applying the fraction rule \frac{a}{c}\pm\frac{b}{c} =\frac{a\pm b}{c}:

a=\frac{c-b}{-2}

Then, apply the fraction rule \frac{a}{-b} =-\frac{a}{b}

a=-\frac{c-b}{2}

5 0
2 years ago
(-2q^4)(-8q^3b^6)<br>help I need to simplify this problem
Montano1993 [528]
Multiply the constants. Multiply the variables according to the rules of exponents.
(-2q^{4})(-8q^{3}b^{6}) = ((-2)(-8))q^{(4+3)}b^{6}\\\\=16q^{7}b^6}
4 0
3 years ago
Calculate the fraction of this recurring decimal. ​
Agata [3.3K]
<h3>Answer:  76/4995</h3>

========================================================

Explanation:

x = 0.0152152...

10x = 0.152152...

10000x = 152.152...

Subtract the last two equations to find that

  • 10000x-10x becomes 9990x on the left side
  • 152.152... - 0.152152... becomes 152 on the right side

We're left with the equation 9990x = 152 which solves to x = 152/9990

Divide both parts of that fraction by 2 so that the fraction fully reduces to 76/4995 which is the final answer

You can use your calculator to see that 76/4995 = 0.0152152152152... which confirms the answer.

8 0
3 years ago
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