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4 years ago

Part A: Which function(s) could have at most 1 x-intercept? Select all that apply.

Mathematics

1 answer:

Art [367]4 years ago

3 0

Answer:

Step-by-step explanation:

The linear functions are the ones that can have at most 1 x-intercept. Specifically, slant lines and vertical lines have this characteristic.

The quadratic function doesn't have this characteristic because there are cases where it intercepts x-axis at two points (concave down).

Additionally, the exponential function doesn't have any x-intercept, because its range is restricted.

Therefore, the right asnwer is the linear function

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See attached image. For part b, my answer is <img src="https://tex.z-dn.net/?f=h%28t%29%3D%5Cfrac%7Bt%5E2%7D%7B100%7D-%5Cfrac%7B

ArbitrLikvidat [17]

Answer:

a) shown

b) h = [sqrt(17) - (5/2)t]²

c) t = 2sqrt(17)/5 seconds

Step-by-step explanation:

V = pi × r² × h

V = pi × 5² × h

V = 25pi × h

a) dV/dt = dV/dh × dh/dt

-5pi × sqrt(h) = 25pi × dh/dt

dh/dt = -sqrt(h)/5

b) 1/sqrt(h) .dh = -5. dt

2sqrt(h) = -5t + c

t = 0, h = 17

2sqrt(17) = 0 + c

c = 2sqrt(17)

2sqrt(h) = -5t + 2sqrt(17)

sqrt(h) = [2sqrt(17) - 5t] ÷ 2

sqrt(h) = sqrt(17) - (5/2)t

Square both sides

h = [sqrt(17) - (5/2)t]²

c) empty: h = 0

0 = [sqrt(17) - (5/2)t]²

sqrt(17) - (5/2)t = 0

(5/2)t = sqrt(17)

t = 2sqrt(17)/5

t = 1.64924225 seconds

sqrt: square root

5 0

4 years ago

Dee whether the bangles are shofe, welte a similarity<br> statement<br> AV<br> X

AleksandrR [38]

Answer:

Step-by-step explanation:

ı do not know

3 0

3 years ago

Write the following number in decimal notation. Three thousand five hundred and seven hundredths

viktelen [127]

3500.07

I hope this helps!

8 0

4 years ago

Read 2 more answers

Solve each equation. I don't know this

MArishka [77]

1. $(2x - 3)(x + 7) = 0$
   $2x^{2} + 14x - 3x - 21 = 0$
   $2x^{2} + 11x - 21 = 0$

   $x = \frac{-11 +/- \sqrt{11^{2} - 4(2)(-21)}}{2(2)}$

   $x = \frac{-11 +/- \sqrt{121 + 168}}{4}$

   $x = \frac{-11 +/- \sqrt{289}}{4}$

   $x = \frac{-11 +/- 17}{4}$

   $x = -2.75 +/- 4.25$
   $x = -2.75 + 4.25$    $x = -2.75 - 4.25$
   $x = 1.5$    <u></u> $x = -7$
---------------------------------------------------------------------------------------------------------- 2. $8x(2x - 5) = 0$
   $8x(2x) - 8x(5) = 0$
   $16x^{2} - 40x = 0$
   $16x^{2} - 4x + 0 = 0$

   $x = \frac{-(-40) +/- \sqrt{(-40)^{2} - 4(16)(0)}}{2(16)}$

   $x = \frac{40 +/- \sqrt{1600 - 0}}{32}$

   $x = \frac{40 +/- \sqrt{1600}}{32}$

   $x = \frac{40 +/- 40}{32}$

   $x = 1.25 +/- 1.25$
   $x = 1.25 + 1.25$       $x = 1.25 - 1.25$
   $x = 2.5$          $x = 0$
----------------------------------------------------------------------------------------------------------
3. $x^{2} + 3x - 10 = 0$

   $x = \frac{-3 +/- \sqrt{3^{2} - 4(1)(-10)}}{2(1)}$

   $x = \frac{-3 +/- \sqrt{9 + 40}}{2}$

   $x = \frac{-3 +/- \sqrt{49}}{2}$

   $x = \frac{-3 +/- {7}}{2}$

   $x = -1.5 +/- 3.5$
   $x = -1.5 + 3.5$    $x = -1.5 - 3.5$
   $x = 2$        $x = -5$
----------------------------------------------------------------------------------------------------------
4. $x^{2} = 13x - 36$
    $x^{2} - 13x + 36 = 13x - 13x - 36 + 36$
    $x^{2} - 13x + 36 = 0$

    $x = \frac{-(-13) +/- \sqrt{(-13)^{2} - 4(1)(36)}}{2(1)}$


    $x = \frac{13 +/- \sqrt{169 - 144}}{2}$

    $x = \frac{13 +/- \sqrt{25}}{2}$

    $x = \frac{13 +/- 5}{2}$

    $x = 6.5 +/- 2.5$
    $x = 6.5 + 2.5$ $x = 6.5 - 2.5$
    $x = 9$    $x = 4$
----------------------------------------------------------------------------------------------------------
5. $3x^{2} - 7x + 2 = 0$

   $x = \frac{-(-7) +/- \sqrt{(-7)^{2} - 4(1)(2)}}{2(3)}$

   $x = \frac{7 +/- \sqrt{49 - 8}}{6}$

   $x = \frac{7 +/- \sqrt{41}}{6}$

   $x = \frac{7 +/- 6.403124237432849}{6}$

   $x = 1.167+/- 1.06718737290547$
   $x = 1.67 + 1.06718737290547$ $x = 1.167 - 1.06718737290547$
   $x = 2.73718737290547$    $x = 0.60281262709453$
----------------------------------------------------------------------------------------------------------
6. $10x^{2} - 10x + 9 = 5x^{2} + 4x + 1$
   $10x^{2} - 5x^{2} - 10x + 10x + 9 - 1 = 5x^{2} - 5x^{2} + 4x + 10x + 1 - 1$
   $5x^{2} + 8 = 14x$
   $5x^{2} - 14x + 8 = 14x - 14x$
   <u /> $5x^{2} - 14x + 8 = 0$

   $x = \frac{-(-14) + \sqrt{(-14)^{2} - 4(5)(8)}}{2(5)}$

   $x = \frac{14 +/- \sqrt{196 - 160}}{10}$

   $x = \frac{14 +/- \sqrt{36}}{10}$ .

   $x = \frac{14 +/- 6}{10}$

   $x = 1.4 +/- 0.6$
   $x = 1.4 + 0.6$       $x = 1.4 - 0.6$
   <u /> $x = 2$ $x = 0.8$

5 0

4 years ago

This is area right???

taurus [48]

Answer:

Yes

Step-by-step explanation:

So permiter is two*lengths plus 2*width of a shape.

Area is the length times the width.

For examplel if a square has a length of 2, and a width of 3 the permiteter is:

2*2+3*3=

4+9

On the other hand, area would be:

2*3

I hope this helps!

4 0

3 years ago