L= length= 1 1/2 yards
A= area= 3 1/2 yards^2
w= width
Area= length * width
plug in numbers you know
3 1/2= (1 1/2)(w)
convert to improper fractions
(3*2+1)/2= ((1*2+1)/2)(w)
7/2= 3/2w
divide both sides by 3/2
7/2 ÷ 3/2= w
to divide fractions, multiply by the reciprocal/inverse of 3/2
7/2 * 2/3= w
(7*2)/(2*3)= w
14/6= w
reduce by 2
7/3= width as improper fraction
OR
2 1/3= width as mixed fraction
ANSWER: The width should be 2 1/3 yards wide (or 7/3 yards wide).
Hope this helps! :)
Answer:
Step-by-step explanation:
![\sqrt[3]{-729a^9b^6} =](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B-729a%5E9b%5E6%7D%20%3D)
Split up each force into horizontal and vertical components.
• 300 N at N30°E :
(300 N) (cos(30°) i + sin(30°) j)
• 400 N at N60°E :
(400 N) (cos(60°) i + sin(60°) j)
• 500 N at N80°E :
(500 N) (cos(80°) i + sin(80°) j)
The resultant force is the sum of these forces,
∑ F = (300 cos(30°) + 400 cos(60°) + 500 cos(80°)) i
… … … + (300 sin(30°) + 400 sin(60°) + 500 sin(80°)) j N
∑ F ≈ (546.632 i + 988.814 j) N
so ∑ F has a magnitude of approximately 1129.85 N and points in the direction of approximately N61.0655°E.
Answer:
-5
Step-by-step explanation:
“x” would be multiplication, right?
Answer:245
Step-by-step explanation:
hope this helps
