The answer to this question would be: p+q+r = 2 + 17 + 39= 58
In this question, p q r is a prime number. Most of the prime number is an odd number. If p q r all odd number, it wouldn't be possible to get 73 since
odd x odd + odd= odd + odd = even
Since 73 is an odd number, it is clear that one of the p q r needs to be an even number.
There is only one odd prime number which is 2. If you put 2 in the r the result would be:
pq+2= 73
pq= 71
There will be no solution for pq since 71 is prime number. That mean 2 must be either p or q. Let say that 2 is p, then the equation would be: 2q + r= 73
The least possible value of p+q+r would be achieved by founding the highest q since its coefficient is 2 times r. Maximum q would be 73/2= 36.5 so you can try backward from that. Since q= 31, q=29, q=23 and q=19 wouldn't result in a prime number r, the least result would be q=17
r= 73-2q
r= 73- 2(17)
r= 73-34=39
p+q+r = 2 + 17 + 39= 58
B). 10.63
Because 7^2=49 and 8^2=64 then 49+64=113 then the square root of 113 is 10.63
Answer: 256
F(8)=512- 768
F(8)= 256
Hopes this helps
Answer:
Ans: -21.87 ≅ -22°C
Step-by-step explanation:
T(x)=-22+44e^-0.03x
Initial temperature (x = 0):
T(0) = = -22 + 44e-0.03(0) = -22 + 44(1) = 22°C
After 18 minutes (x = 18):
T(18) = -22 + 44e-0.03(18) = -21.87°C ≅ -22°C
Answer:
a)
AB is on the latitude 30°N.
<u>Find AB:</u>
- AB = 2*3.142*6400*cos 30°*(32+35)/360 = 6482.15 km
BC is along longitude 35°W
<u>Find BC:</u>
- BC = 2*3.142*6400*(30 + 20)/360 = 5585.77 km
<u>Total distance traveled:</u>
- 6482.15 + 5585.77 = 12067.92 km
<u>Convert the distance to nautical miles:</u>
12067.92/1.86 = 6488.13 nautical miles
b)
<u>Find the average speed:</u>
- 6488.13/22 = 294.92 nautical miles / hour
<u>Note</u>. <em>This is unrealistically high speed for a ship, this must be a plane or the time given wrong.</em>
