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Tasya [4]
2 years ago
9

Three forces of 300 N in the direction of N30E, 400N in the direction of N60E and

Mathematics
1 answer:
andreyandreev [35.5K]2 years ago
4 0

Split up each force into horizontal and vertical components.

• 300 N at N30°E :

(300 N) (cos(30°) i + sin(30°) j)

• 400 N at N60°E :

(400 N) (cos(60°) i + sin(60°) j)

• 500 N at N80°E :

(500 N) (cos(80°) i + sin(80°) j)

The resultant force is the sum of these forces,

∑ F = (300 cos(30°) + 400 cos(60°) + 500 cos(80°)) i

… … …  + (300 sin(30°) + 400 sin(60°) + 500 sin(80°)) j N

∑ F ≈ (546.632 i + 988.814 j) N

so ∑ F has a magnitude of approximately 1129.85 N and points in the direction of approximately N61.0655°E.

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<u>Step-by-step explanation:</u>

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3 years ago
At a high school, students can choose between three art electives, four history electives, and five computer electives. Each stu
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Answer:

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here is a link that will hopefully help.

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