Answer: 7:10
Step-by-step explanation: You are asked to find the ratio of sweaters to pairs of jeans. All you do is write the 7 sweaters and the 10 pairs of jeans. And you get a ratio of 7:10. Since this cannot be reduced any further, you just leave it as it is.
Hope this helps.
To solve this problem, it is easiest to set up a system of equations. Let's let the variable s represent the cost of a shirt and the variable j represent the cost of jackets. According to the given information, we can set up the following equations (because cost multiplied by quantity yields price):
3s + 4j = 360
1s + 3j = 220
Next, we can manipulate the second equation so that it equals s in terms of j. We do this by subtracting 3j from both sides of the equation, as shown below:
s = 220 - 3j
After that, we should substitute in this value for the variable s in the first equation.
3(220-3j) + 4j = 360
Next, we should use the distributive property to simplify the left side of the equation.
660 - 9j + 4j = 360
Then, we should simplify the left side of the equation by combining like terms.
660 - 5j = 360
After, we can subtract 660 from both sides of the equation to get the variable term alone.
-5j = -300
Finally, we should divide both sides of the equation by -5 in order to get the variable j alone.
j = 60
Now that we know the value of the variable j, we should substitute this value into one of the original equations and solve using division and subtraction to isolate the variable.
3s + 4j = 360
3s + 4(60) = 360
3s + 240 = 360
3s = 120
s = 40
Therefore, the cost of one shirt is $40.
Hope this helps!
Answer:
0.35
Step-by-step explanation:
The purple line is showing / represents exponential growth
Answer:
B
Step-by-step explanation:
Stopping at a stoplight means that Chris's speed would be zero on the graph. The times that his speed is zero are times t = 0, t = 2 min, t = 11 min, and t = 21 min. Because the graph shows his speed from the time he left his house (at t = 0) to the time he arrived at the theater (at t = 21 min), the most likely times he stopped at stoplights are times t = 2 min and t = 11 min.
