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3 years ago

Please help me draw the model

Mathematics

1 answer:

Elis [28]3 years ago

5 0

Answer:

Step-by-step explanation:

1/3 plus 1/3 =2/6 then you do 2/6 plus 2/6 and get 4/6 then you cant do 4/6 plus 4/6 because it will be bigger than 5/6

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For the figures below, assume they are made of semicircles, quarter circles and squares. For each shape, find the area and perim

Marina86 [1]

Area of the shaded region $$=36(\pi -2)$ square cm

Perimeter of the shaded region $=6 (\pi + 2\sqrt 2)$ cm

Solution:

Radius of the quarter of circle = 12 cm

Area of the shaded region = Area of quarter of circle – Area of the triangle

$$=\frac{1}{4} \pi r^2 - \frac{1}{2} bh$

$$=\frac{1}{4} \pi \times 12^2 - \frac{1}{2} \times 12 \times 12$

$$=36\pi -72$

$$=36(\pi -2)$ square cm.

Area of the shaded region $$=36(\pi -2)$ square cm

Using Pythagoras theorem,

$AC^2=AB^2+BC^2$

$AC^2=12^2+12^2$

$AC^2=288$

Taking square root on both sides of the equation, we get

$AC= 12\sqrt 2$ cm

Perimeter of the quadrant of a circle = $\frac{1}{4} \times 2\pi r$

$$=\frac{1}{4} \times 2 \times \pi \times 12$

$$=6 \pi$ cm

Perimeter of the shaded region = $6 \pi + 12\sqrt 2$ cm

$=6 (\pi + 2\sqrt 2)$ cm

Hence area of the shaded region $$=36(\pi -2)$ square cm

Perimeter of the shaded region $=6 (\pi + 2\sqrt 2)$ cm

6 0

3 years ago

Use the power-reducing formulas to rewrite the expression as an equivalent expression that does not contain powers of trigonome

ratelena [41]

Answer:

$x = 0.175\cdot (1-\cos 4\cdot \theta)$

Step-by-step explanation:

Let use the following trigonometric identities:

$\sin^{2}\theta = \frac{1-\cos 2\cdot \theta}{2} \\\cos^{2}\theta = \frac{1+\cos 2\cdot \theta}{2}$

Then, the equation is simplified by substituting its components:

$x = 1.40\cdot \left(\frac{1-\cos 2\cdot \theta}{2} \right)\cdot \left(\frac{1+\cos 2\cdot \theta}{2} \right)$

$x = 0.35\cdot (1-\cos^{2}2\cdot \theta)$

$x = 0.35\cdot \sin^{2}2\cdot \theta$

$x = 0.35\cdot \left(\frac{1-\cos 4\cdot \theta}{2} \right)$

$x = 0.175\cdot (1-\cos 4\cdot \theta)$

7 0

4 years ago

Read 2 more answers

How is solving for speed similar to solving for time?

vichka [17]

Answer:

They both use the same units of measure.

Step-by-step explanation:

3 0

3 years ago

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A restaurant offers a $12 dinner special that has 77 choices for an appetizer, 1010 choices for an entrée, and 44 choices for

krok68 [10]

<span>280 I'm assuming that this question is badly formatted and that the actual number of appetizers is 7, the number of entres is 10, and that there's 4 choices of desserts. So let's take each course by itself. You can choose 1 of 7 appetizers. So we have n = 7 After that, you chose an entre, so the number of possible meals to this point is n = 7 * 10 = 70 Finally, you finish off with a dessert, so the number of meals is: n = 70 * 4 = 280 Therefore the number of possible meals you can have is 280. Note: If the values of 77, 1010 and 44 aren't errors, but are actually correct, then the number of meals is n = 77 * 1010 * 44 = 3421880 But I believe that it's highly unlikely that the numbers in this problem are correct. Just imagine the amount of time it would take for someone to read a menu with over a thousand entres in it. And working in that kitchen would be an absolute nightmare.</span>

5 0

3 years ago

Which expression can be used to determine the length of segment AB? On a coordinate plane, triangle A B C has points (4, 3), (ne

JulijaS [17]

Answer:

StartRoot 2 squared + 6 squared EndRoot

Step-by-step explanation:

we have

A(4,3) and B(-2,1)

we know that

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$