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harina [27]
3 years ago
15

Solve the following Equations A)x-1=5 B)2m-1=9

Mathematics
2 answers:
Vinil7 [7]3 years ago
7 0

Answer:

x=6 m=5

Step-by-step explanation:

x-1=5

x=5+1

x=6

2m-1=9

2m=9+1

2m=10

m=10/2

m=5

Allisa [31]3 years ago
6 0
For some reason its not letting me send you it so like here is a pic

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Complement and supplement of a 19
Tems11 [23]

well first the complement I 90-19=71

and supplement is 180-19=161

3 0
3 years ago
What does k equal in the equation y = kx3, so that it represents the graph shown?
Oxana [17]
Without the graph it is impossible the find the value of K
8 0
3 years ago
Consider the logarithms base 5. For each logarithmic expression below, either calculate the value of the expression or explain w
Tom [10]

Answer:

log₅(3125) = 5

Step-by-step explanation:

Given:

log₅(3125)

Now,

using the property of log function that

logₐ(b) = \frac{\log(b)}{\log(a)}

thus,

Therefore, applying the above property, we get

⇒ \frac{\log(3125)}{\log(5)}   (here log = log base 10)

now,

3125 = 5⁵

thus,

⇒  \frac{\log(5^5)}{\log(5)}

Now,

we know from the properties of log function that

log(aᵇ) = b × log(a)

therefore applying the above property we get

⇒ \frac{5\log(5)}{\log(5)}

or

⇒ 5

Hence,

log₅(3125) = 5

8 0
3 years ago
12. (2v^3 - v + 8) + (-v^3 + v - 3)<br><br> 14. (4h^3 + 3h + 1) - (-5h^3 + 6h - 2)
Lana71 [14]
12. On addition, you can just combine like terms.
2v^3+(-v^3)=v^3
-v+v cancels each other out
8+(-3)=5
So you have v^3+5

14 On subtraction, you have to remember to distribute the negative sign so after you do that you have:
4h^3+3h+1+5h^3-6h+2
Then you can combine like terms
4h^3+5h^3=9h^3
3h-6h=-3h
1+2=3
So you end up with:
9h^3-3h+3

Hope that helps and feel free to ask any questions.
7 0
3 years ago
Help soon!!! tysm!!!
victus00 [196]

Answer:

36-b  ^ { 2  }  -c  ^ { 2  }  +2bc\\36-\left(b^{2}+c^{2}-2bc\right) \\6^{2}-\left(b-c\right)^{2} \\\boxed{\left(6-b+c\right)\left(6+b-c\right) }

Hope it helps ⚜

7 0
2 years ago
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