well first the complement I 90-19=71
and supplement is 180-19=161
Without the graph it is impossible the find the value of K
Answer:
log₅(3125) = 5
Step-by-step explanation:
Given:
log₅(3125)
Now,
using the property of log function that
logₐ(b) = 
thus,
Therefore, applying the above property, we get
⇒
(here log = log base 10)
now,
3125 = 5⁵
thus,
⇒ 
Now,
we know from the properties of log function that
log(aᵇ) = b × log(a)
therefore applying the above property we get
⇒ 
or
⇒ 5
Hence,
log₅(3125) = 5
12. On addition, you can just combine like terms.
2v^3+(-v^3)=v^3
-v+v cancels each other out
8+(-3)=5
So you have v^3+5
14 On subtraction, you have to remember to distribute the negative sign so after you do that you have:
4h^3+3h+1+5h^3-6h+2
Then you can combine like terms
4h^3+5h^3=9h^3
3h-6h=-3h
1+2=3
So you end up with:
9h^3-3h+3
Hope that helps and feel free to ask any questions.