solution:
I choose 5 women from a pool of 10 in 10C2 ways.
I choose 5 men from a pool of 12 in 12C2 ways.
So total number of ways of choosing in 10C2 x 12C2. Now I need to arrange them in 5 pairs. This is where I have a different solution. The solution says that there are 5! ways to arrange them in pairs.
But I cant seem to understand why? My reasoning is that for first pair position I need to choose 1 man from 5 and 1 woman from 5. So for the first position I have 5 x 5 choices (5 for man and 5 for woman). Similarly for the second position I have 4 x 4 choices and so on. Hence the total ways are 5! x 5!
So I calculate the total ways as 10C2 * 12C2 * 5! * 5!. Can anyone point the flaw in my reasoning for arranging the chosen men and women in pairs.
Answer:
D 16% increase
Step-by-step explanation:
This is ez
just did this stuff in pre algebra
The correct answer is: D.) 6 7/8
Step-by-step explanation:
Given
2 3/4 divided 2/5
In order to divide two fractions, the reciprocal of the divisor is taken and then multiplied with the dividend.
So,
To solve
Hence
The correct answer is: D.) 6 7/8
Keywords: Fractions, division
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