1- Leave the 1st case empty
2- Write on the 1st row each element of the trinomial in each case
3-Write on the 1st column in each case each of the element of the binomial
║ y² -3y 9
----------- ║-----------------------------------------------------
y ║ y³ -3y² 9y
----------- ║---------------------------------------------------
3 ║ 3y² -9y 27
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TOTAL║(y³+3y²) +(-3y²-9y) + ( 9y+27)
If you add the Total you will get: (A) Y³+27
R = { (x,y): 3x-y=0 }
The condition is 3x=y so that's not going to be any of these things.
R is reflexive if (x,x)∈R for all x. Let's check.
3x - y = 3x - x = 2x ≠ 0 necessarily. NOT REFLEXIVE
R is symmetric if (x,y)∈R → (y,x)∈R. Let's check.
(x,y)∈R so
3x-y = 0
y = 3x
Is (y,x)∈R. That would be true if 3y-x=0
3y - x = 3(3x) - x = 8x ≠ 0 necessarily NOT SYMMETRIC
R is transitive if (x,y)∈R and (y,z)∈R → (x,z)∈R. Let's check.
3x-y = 0 so y=3x
3y-z = 0 so z=3y = 9x
3x - z = 3x - 9x = -6x ≠ 0 necessarily NOT TRANSITIVE
Amount of oil sandi has = 2 1/3 * 12
= 7/3 * 12 = 7*4 = 28 quarts
