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LiRa [457]
3 years ago
11

If you vertically compress the absolute value parent function f(x)=lxl, by a factor of 3, what is the equation of the new functi

on?
A. g(x) = |3x|
B. g(x) = |x-3|
C. g(x) = 1/3x
D. g(x) = 3|x|
Mathematics
1 answer:
ira [324]3 years ago
8 0

Answer:

The equation of the new function will be the option C i.e. g(x) = 1/3lxl

Step-by-step explanation:

As the absolute value parent function is f(x)=lxl.

In order to vertically compress or stretch the parent function, we must have to multiply the function with a constant number.

Lets suppose that constant number is 'a'.

If a function is multiplied with a constant number i.e 'a', the function will compress or stretch depending upon the value of 'a'.

So,

If a > 1, then the function will vertically stretch.  

But, it if 0 < a < 1, then the function will vertically compress.

So, from the available options in the question, the parent function f(x)=lxl will be multiplied by 1/3 if we want to vertically compress the function.

Hence, the equation of the new function

will be the option C i.e. g(x) = 1/3lxl

keywords: absolute value, vertically compression, function

Learn more about compression from /brainly.com/question/11334530

#learnwithBrainly

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Step-by-step explanation:

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A nationwide study of American homeowners revealed that 65% have one or more lawn mowers. A lawnequipment manufacturer, located
GenaCL600 [577]

Answer:

z=\frac{0.684 -0.65}{\sqrt{\frac{0.65(1-0.65)}{497}}}=1.589  

p_v =P(z>1.589)=0.056  

If we compare the p value obtained with the significance level assumed \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of homes in Omaha with one or more lawn mowers is not ignificantly higher than 0.65

Step-by-step explanation:

Data given and notation

n=497 represent the random sample taken

X=340 represent the homes in Omaha with one or more lawn mowers

\hat p=\frac{340}{497}=0.684 estimated proportion of homes in Omaha with one or more lawn mowers

p_o=0.65 is the value that we want to test

\alpha represent the significance level

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to test the true proportion of homes in Omaha with one or more lawn mowers is higher than 0.65.:  

Null hypothesis:p\leq 0.65  

Alternative hypothesis:p > 0.65  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.684 -0.65}{\sqrt{\frac{0.65(1-0.65)}{497}}}=1.589  

Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The next step would be calculate the p value for this test.  

Since is a right tailed test the p value would be:  

p_v =P(z>1.589)=0.056  

If we compare the p value obtained with the significance level assumed \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of homes in Omaha with one or more lawn mowers is not ignificantly higher than 0.65

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