Let student tickets be s and adult tickets be a. The number of tickets sold of both adult and student then is s + a = 396. If each student ticket costs $3, then we represent the money equation by tacking the dollar amount onto the ticket. 3s is the cost of one student ticket. 4a is the cost of an adult ticket. The total money from the sales of both is 4a + 3s = 1385. We now have a system of equations we can solve for a and s. If s+a=396, then s = 396-a. We will sub that into the second equation to get 4a + 3(396-a) = 1385. Distributing we have 4a+1188-3a=1385. a = 197. That means there were 197 adult tickets sold. If s + a = 396, then s + 197 = 396 and s = 199. 197 adult tickets and 199 student tickets. There you go!
Answer:
.12 = 12/100 or 4/25 I'm not sure if I'm correct but I tried, I'll try solving the other ones and update you
.250 = 25/100 which simplified is 5/20
When multiplying numbers of the same base , we add the powers.
Example:
2^2 * 2^3 = 2^(2+3) = 2^5
For the givens:
The seventh root of x can be written as x^(1/7)
Now, we need to multiply x^(1/7) by x^(1/7) by x^(1/7)
These numbers have the same base which is "x", therefore, we will just add the power.
This means that:
x^(1/7) * x^(1/7) * x^(1/7) = x^(1/7 + 1/7 + 1/7) = x^(3/7)
Therefore, the correct choice is the first one: x^(3/7)
Answer:
−15w2−225w hope this helped
Answer:
b & d
Step-by-step explanation:
