Find midpoint of segment.
(-1,1), (7,-5)
Find slope of line which passes through (-1,1) and (7,-5).
The slope of perpendicular line is negative reciprocal value of m.
Write quation of line which slope is
and passes throug the point (3,-2).
Answer:
(100)^0=1
Step-by-step explanation:
This follows the laws of indices
Given:
A plane is normal to the vector = -2i+5j+k
It contains the point (-10,7,5).
To find:
The component equation of the plane.
Solution:
The equation of plane is
Where, 
is the point on the plane and 
is normal vector.
Normal vector is -2i+5j+k and plane passes through (-10,7,5). So, the equation of the plane is
Therefore, the equation of the plane is .
14. sometimes, you can have a 45-45-90 or 60-30-90 triangle (degrees)
sometimes true
15. always
16. never, paralellogram has 2 pairs of paralell sides, trapezoid has 1
17.always
18. sometimes
19. always
20. always
