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wolverine [178]
3 years ago
14

Can someone please help with finding the domain and range

Mathematics
1 answer:
Zanzabum3 years ago
5 0

Answer:

Step-by-step explanation:

(0,75) , (15,0)

domain: (0,15)

range: (0,75)

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Barb went to grottos pizza and ordered 7 large pizzas Her total bill was $49
Naddika [18.5K]

My answer would be c that my answer hope this helps

8 0
3 years ago
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Hi can any one please help me I really need help please please let me know ya
aalyn [17]
A. V= l x b x h
= 5cm x 4cm x 10cm
= 200 squared centimetres

C. V= S squared x h divided by 3
= 15cm x 17cm divided by 3
= 85 squared centimetres

D. V= b x h x l divided by 2
= 8cm x 10cm x 13cm divided by 2
= 520 cubed centimetres

Well am not sure about the other two but I hope this helps ya
5 0
3 years ago
50 PTS. Andrew loves candy so much that after returning from Costco with some candy, he eats 40% of the candy he just bought. Th
Helga [31]

Answer: 5%

Step-by-step explanation:

100% - 40%

= 60% or 3/5 - first day

2/5 of 3/5 = 6/25 = 24% eaten

36% left - 2nd day

2/5 of 6/25 = 14.4% eaten

= 21.6 % left - 3rd day

2/5 of 21.6 = 8.64% eaten

= 12.96 % left - 4th day

2/5 of 12.96%  = 5.184 eaten

= 7.776% left - 5th day

2/5 of 7.776% = 3.1104% eaten

= 4.6656% left after the 6th day

rounded off to 5% after the 6th day

6 0
3 years ago
12a^3b^2 +18a²b^2 – 12ab^2<br> Factor completely
AleksAgata [21]

The factorization of 12a^3b^2 +18a²b^2 – 12ab^2 is 6 a b^{2}(a+2)(2 a-1)

<u>Solution:</u>

Given, expression is 12 a^{3} b^{2}+18 a^{2} b^{2}-12 a b^{2}

We have to factorize the given expression completely.

Now, take the expression

12 a^{3} b^{2}+18 a^{2} b^{2}-12 a b^{2}

Taking b^2 as common term,

b^{2}\left(12 a^{3}+18 a^{2}-12 a\right)

Taking "a" as common term,

b^{2}\left(a\left(12 a^{2}+18 a-12\right)\right)

Taking "6" as common term,

b^{2}\left(a\left(6\left(2 a^{2}+3 a-2\right)\right)\right)

Splitting "3a" as "4a - a" we get,

b^{2}\left(a\left(6\left(2 a^{2}+4 a-a-2\right)\right)\right)

\begin{array}{l}{b^{2}(a(6(2 a(a+2)-1(a+2))))} \\\\ {b^{2}(a(6((a+2) \times(2 a-1))))} \\\\ {6 a b^{2}(a+2)(2 a-1)}\end{array}

Hence, the factored form of given expression is 6 a b^{2}(a+2)(2 a-1)

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3 years ago
Will give brainliest please answer
lubasha [3.4K]

Answer:

1 to column a

2 to column b

3 to collumn a

4 to column a

5 to column b

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Step-by-step explanation:

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