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Mila [183]
4 years ago
7

How many students preferred music

Mathematics
2 answers:
lisabon 2012 [21]4 years ago
6 0

By cross-multiplying 23/100 and X/200, you would get C. 46.

iris [78.8K]4 years ago
5 0

The correct answer would be:

46.

Multiply 23/100 by 2 to get 46/100.

Hope that helps! Have a good day/night! c:

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Can someone help me with 5 and 6
Tom [10]
Number 5 is 42.2

.............
7 0
3 years ago
Which of the following is true?​ a. ​Stratification is utilized to create a z-score across data sets. b. ​Summarization provides
Mrac [35]

Option D

Stratification is the splitting of data into case-specific tables is true.

<u>Explanation:</u>

Stratification is a method or configuration of layers, groups, or sections. Stratification intends to classify data/characters/objects into distinct groups or layers. Stratification consists of splitting the group into subsets (named strata) within individual of which an autonomous sample is chosen.

Stratified sampling in statistics is applied to highlight contrasts within groups in a population, as objected to simple random sampling. Stratification is the part of something, primarily society, into various groups or layers.

4 0
3 years ago
A population of voters contains 46% Republicans, 45% Democrats and the rest are Independents. Assume 50% of Republicans, 40% of
ICE Princess25 [194]

Answer:

The probability is 0.18

Step-by-step explanation:

Here, we are interested in calculating a conditional probability;

Let the event that a voter is a Republican be R , the event that a voter is a Democrat be D and that a voter is an independent is I

Let the event that the election issue is favored be F

We have the following probabilities;

P(R) = 46% = 0.46

P(D) = 45% = 0.45

P(I) = 1-0.45-0.46 = 0.09

The conditional probability we want to calculate is;

P(D | F) which can be read as probability of event D given event F

From the question, we can identify the following conditional probabilities;

P(F|R) = 0.46 * 0.5 = 0.23 (0.5 is gotten from 50% = 50/100)

P(F | D) = 0.45 * 0.4 = 0.18

P( F | I) = 0.09 * 0.6 = 0.054

P(F) = 0.054 + 0.18 + 0.23 = 0.464

Mathematically; From Baye’s theorem

P( D | F) ={ P ( F | D) * P(D) }/ P(F)

P( D | F) = (0.18 * 0.45)/0.464 = 0.1745

7 0
3 years ago
Assume that the annual household expenditure on sugar is approximately normally distributed with a mean of $8.22 and a standard
irina1246 [14]

 To solve this problem, we will have to make use of the z statistic. The formula for the z score is given as:

z = (x – u) / s

where,

x is the sample value = more than $10.00

u is the sample mean = $8.22

s is the standard deviation = $1.10

 

Substituting the values into the equation to solve for z:

<span>z = (10 – 8.22)  / 1.10</span>

z = 1.78 / 1.10

z = 1.62

 

We then look for the p value using the standard distribution tables at the specified z score value = 1.62. Since this is a right tailed test, therefore the p value is:

p = 0.0526

or

p = 5.26%

 

<span>Therefore there is a 5.26% probability that a household spent more than $10.00</span>

5 0
3 years ago
Show all work for full credit.
SSSSS [86.1K]

Answer:

−1,−4,−9,−14,-19,-24,-29,-34,-39,-44,-49,-54

Step-by-step explanation:

Sum is 3 then 5

4 0
3 years ago
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