3 years ago

How many real zeroes does y = ( x + 8 )^3 + 9 have?

2 answers:

algol133 years ago

6 0

It looks like y = x^3 only shifted to the left 8 units and up 9 units

So i think the amount of real zeroes that this equation has is :

1 Real zero

hope this helps

Vaselesa [24]3 years ago

5 0

This is just the graph of y = x^3, moved 8 units to the left and 9 units up.
It has one real zero.

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A man drove 5 miles directly east from his home, made a left turn at an intersection, and then traveled 11 miles duc north to hi

lubasha [3.4K]

Answer: About 12.083

Explanation:
In order to solve this you would use Pythagorean theorem.

You are given the length of the two legs (5 and 11)

So by plugging in 5 and 11 into A Squared plus B Squared = C Squared, you get that C^2= 146.

By finding the square root of both sides you get square root of 146, which is approximately 12.803