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adelina 88 [10]

3 years ago

6

How many real zeroes does y = ( x + 8 )^3 + 9 have?

2 answers:

algol133 years ago

6 0

It looks like y = x^3 only shifted to the left 8 units and up 9 units

So i think the amount of real zeroes that this equation has is :

1 Real zero

hope this helps

Vaselesa [24]3 years ago

5 0

This is just the graph of y = x^3, moved 8 units to the left and 9 units up.
It has one real zero.

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Licemer1 [7]

Answer:

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Which equation has infinite solutions?

AnnyKZ [126]

The equation that has an infinite number of solutions is $2x + 3 = \frac{1}{2}(4x + 2) + 2$

<h3>How to determine the equation?</h3>

An equation that has an infinite number of solutions would be in the form

a = a

This means that both sides of the equation would be the same

Start by simplifying the options

3(x – 1) = x + 2(x + 1) + 1

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-3x - 4 = -3x - 2

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2x + 3 = 2x + 1 + 2

2x + 3 = 2x + 3

Subtract 2x

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<u>Complete question</u>

Which equation has infinite solutions?

3(x – 1) = x + 2(x + 1) + 1

x – 4(x + 1) = –3(x + 1) + 1

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$\frac{92.5}{105}$

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$\frac{185}{210} \div \frac{5}{5}$

$\frac{37}{42}$

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