3 years ago

How many real zeroes does y = ( x + 8 )^3 + 9 have?

2 answers:

algol133 years ago

6 0

It looks like y = x^3 only shifted to the left 8 units and up 9 units

So i think the amount of real zeroes that this equation has is :

1 Real zero

hope this helps

Vaselesa [24]3 years ago

5 0

This is just the graph of y = x^3, moved 8 units to the left and 9 units up.
It has one real zero.

You might be interested in

With a picture eqation

butalik [34]

I don’t mean to take point but i do not see a picture :(

7 0

2 years ago

Read 2 more answers

"Death Valley Hike"

Amanda [17]

I would go with Either E or A

7 0

2 years ago

Read 2 more answers

Please help this is the last problem I need

tangare [24]

Answer:

$sin 54 = \frac{x}{14}$

Step-by-step explanation:

$sine = \frac{opposite}{hypotenuse}$

Side z is the adjacent, since it is next to the angle you are solving for.

Side x is the opposite, since it is opposite the angle you are solving for.

The side measuring 14 is the hypotenuse, since it is across from the right angle.

$sin 54 = \frac{x}{14}$

8 0

2 years ago

HELP

ExtremeBDS [4]

Answer:B,C,A,B

Step-by-step explanation

4 0

3 years ago

Name this three dimensional figure

vodomira [7]

Answer:

Square Pyramid

Step-by-step explanation:

Hope this helps!

8 0

2 years ago