Write the equation of the inequality in slope-intercept form. (Picture below)

-5y + 8 = 3y + 10. Calculate and show work

maksim [4K]

2x+3=[email protected]x=6(2)(6)+3=1515=15

4 0

3 years ago

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Adele has 3 64-ounce cartons of orange juice and 3 48-ounce cans of apple juice. How much juice does she have altogether?

ale4655 [162]

I think if u add 364+348 you will get 712

4 0

3 years ago

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X + y = -5 determine x-intercept and y-intercept

Fofino [41]

Very easy question.

To find x intercept: Multiply y by 0. You get x=-5.

To find y intercept: Multiply x by 0. You get y=-5.

4 0

3 years ago

Consider a chemical company that wishes to determine whether a new catalyst, catalyst XA-100, changes the mean hourly yield of i

kolezko [41]

Answer:

Null hypothesis: $\mu = 750$

Alternative hypothesis: $\mu \neq 750$

$t=\frac{811-750}{\frac{19.647}{\sqrt{5}}}=6.943$

$p_v =2*P(t_{4}>6.943)=0.00226$

If we compare the p value and a significance level assumed $\alpha=0.05$ we see that $p_v$ so we can conclude that we reject the null hypothesis, and the actual true mean is significantly different from 750 pounds per hour.

Step-by-step explanation:

Data given and notation

Data: 801, 814, 784, 836,820

We can calculate the sample mean and sample deviation with the following formulas:

$\bar X =\frac{\sum_{i=1}^n X_i}{n}$

$s=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

$\bar X=811$ represent the sample mean

$s=19.647$ represent the standard deviation for the sample

$n=5$ sample size

$\mu_o =750$ represent the value that we want to test

$\alpha$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses to be tested

We need to conduct a hypothesis in order to determine if the mean is different from 750 pounds per hour, the system of hypothesis would be:

Null hypothesis: $\mu = 750$

Alternative hypothesis: $\mu \neq 750$

Compute the test statistic

We don't know the population deviation, so for this case is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

We can replace in formula (1) the info given like this:

$t=\frac{811-750}{\frac{19.647}{\sqrt{5}}}=6.943$

Now we need to find the degrees of freedom for the t distirbution given by:

$df=n-1=5-1=4$

What do you conclude?

Compute the p-value

Since is a two tailed test the p value would be:

$p_v =2*P(t_{4}>6.943)=0.00226$

If we compare the p value and a significance level assumed $\alpha=0.05$ we see that $p_v$ so we can conclude that we reject the null hypothesis, and the actual true mean is significantly different from 750 pounds per hour.

4 0

3 years ago

two brothers marco and fernando are training for a marathon marco runs at a rate of 6miles per hor. Fernando funs at at a rate o

satela [25.4K]

We know that
speed=distance/time
solve for time
time=distance/speed

in this problem
Marco runs at a rate of 6 miles per hour.
Fernando funs at a rate of 7.2 miles per hour
Difference=7.2-6=1.2 miles/hour
so
speed=1.2 miles/hour
distance=0.3 miles
time=?
time=distance/speed-----> 0.3/1.2-----> 0.25 hour-----> 0.25*60=15 minutes

the answer is
0.25 hour (15 minutes)

Alternative Method
Let
x---------> Fernando's distance when Marco is 0.3 miles apart

Fernando funs at a rate of 7.2 miles per hour
for distance =x
time=x/7.2------> equation 1

Marco runs at a rate of 6 miles per hour.
for distance=x-0.30
time=(x-0.30)/6------> equation 2

equate equation 1 and equation 2
7.2*(x-0.3)=6x-----> 7.2x-2.16=6x
7.2x-6x=2.16------> x=2.16/1.2-------> x=1.8 miles

time=x/7.2-----1.8/7.2=0.25 hour

6 0

3 years ago