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3 years ago

Find the different quotient f(x)=4x-7

Mathematics

1 answer:

bulgar [2K]3 years ago

4 0

Answer:

Step-by-step explanation:

if its the difference quotient it is 4

Find f ( x + h ) and f ( x ) , and plug these values into the difference quotient formula.

ps can u mark me brainliest if i got it right plz

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The curves r1(t) = 4t, t2, t3 and r2(t) = sin(t), sin(5t), 2t intersect at the origin. find their angle of intersection, θ, corr

san4es73 [151]

First get the tangent vectors by differentiating r1 and r2
$r_1 '(t) = (4,2t,3t^2) \\ \\ r_2'(t) = (cos (t), 5 cos(5t), 2)$
Evaluate at t=0
$r_1' = (4,0,0) \\ \\ r_2' = (1,5,2)$

Use identity for angle between 2 vectors:
$u*v = |u| |v| cos \theta$

Evaluate dot product and unit vectors:
$u*v = (4,0,0)*(1,5,2) = 4 \\ \\ |u| = \sqrt{4^2 +0^2+0^2} = 4 \\ \\ |v| = \sqrt{1^2 + 5^2+2^2} = \sqrt{30}$

Sub into identity and solve for theta:
$4 = 4 \sqrt{30} cos \theta \\ \\ cos\theta = \frac{1}{\sqrt{30}} \\ \\ \theta = 79.48$

Answer:
Angle of intersection is about 79 degrees.

5 0

4 years ago

Identify the quadratic function from the four functions

Alchen [17]

Quadratic Function is a function that takes the equation form of:

$\large \boxed{y = a {x}^{2} + bx + c}$

where a ≠ 0. However the form of Quadratic Function above can also be called "standard form" or general form because it is commonly used when defining the function. Quadratic Functions also have other two forms which are intercept form and vertex form.

Vertex Form

$\large \boxed{y = a {(x - h)}^{2} + k}$

Intercept Form

$\large \boxed{y = (ax - b)(bx - c)}$

The intercept form can be expressed as y = (x-a)(x-b) depending on the other perspective.

If you look at all four functions, you will notice that only two of functions have the second degree as highest degree while the third function has third degree as highest and fourth function has fourth degree. Recall the definition of Quadratic Function above that the highest degree of Quadratic Function can only be second degree (squared, x² as example). Therefore we can rule out the x³ and -2x⁴ away.

So our only quadratic functions are:

$\large{ \begin{cases}y = - {x}^{2} - 4 \\ y = {(x - 1)}^{2} - 7 \end{cases}}$

As for the f(x) = -x²-4. The equation is in standard form which is y = ax²+bx+c. The second equation is in vertex form which is y = a(x-h)²+k.

Answer

The only quadratic functions are f(x) = -x²-4 and f(x) = (x-1)²-7
-x²-4 is in standard form.
(x-1)²-7 is in vertex form.

Hope this helps and let me know if you have any doubts.

Also let me know if you want me to convert the function into other form. For ex. convert the vertex form to standard form.

Happy Learning and Good Luck with your assignment!

4 0

3 years ago

Solve for an Angle in right triangles

Vedmedyk [2.9K]

Answer:

B = 56.25

Step-by-step explanation:

Since this is a right triangle, we can use trig functions

cos theta = adjacent/ hypotenuse

cos B = 5/9

Take the inverse cos of each side

cos ^-1 (cos B) = cos ^-1 (5/9)

B =56.2510114

To the nearest hundredth

B = 56.25

8 0

3 years ago

The question is 2+2=__

olasank [31]

4

Jqhehajahsiahajqisjdha

8 0

3 years ago

Answer please and thank you

PSYCHO15rus [73]

Answer:

s = 11.97

Step-by-step explanation:

4 0

3 years ago

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