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4 years ago

What are the period and phase shift for f(x) = −4 tan(x − π)?

Mathematics

1 answer:

777dan777 [17]4 years ago

8 0

This is the answer Period: π; phase shift: x = π

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The function f(x) = 40sin(0.1x + 12) + 50 represents the number of items, f(x), made in a factory each day for x days. The data

Goshia [24]

Answer: 11,31

Step-by-step explanation: on edge

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3 years ago

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What is the indefinite integral of 1/xln(x^3) dx?

Aleonysh [2.5K]

Hello,

$\int\limits{ \dfrac{ln(x^3)}{x}} \, dx = 3*\int\limits{\frac{ln(x)}{x}} \, dx \\\\=3*\dfrac{ln^2(x)}{2} +C$

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3 years ago

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3.5821568896×10−10 What does this equal?

lana [24]

Answer:

25.821568896

Step-by-step explanation:

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3 years ago

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The accompanying summary data on total cholesterol level (mmol/l) was obtained from a sample of Asian postmenopausal women who w

dimulka [17.4K]

Answer:

99% CI:

$-4.637\leq\mu_v-\mu_o\leq 3.737$

Step-by-step explanation:

We have to calculate a 99%CI for the difference of means for the vegan and the omnivore.

First, we have to estimate the standard deviation

$s_{Md}=\sqrt{\frac{2MSE}{n_h}}$

The MSE can be calculated as

$MSE=\frac{(SSE_1+SSE_2)}{df} =\frac{(n_1s_1)^2+(n_2*s_2)^2}{n_1+n_2-2}\\\\MSE=\frac{(85*1.05)^2+(96*1.20)^2}{85+96-2}=\frac{7965.56+13272.04}{179} =118.65$

The weighted sample size nh can be calculated as

$n_h=\frac{2}{1/n_1+1/n_2}=\frac{2}{1/85+1/96}=\frac{2}{0.0222} =90.16$

The standard deviation then becomes

$s_{Md}=\sqrt{\frac{2MSE}{n_h}}=\sqrt{\frac{2*118.65}{90.16}}=\sqrt{2.632} =1.623$

The z-value for a 99% confidence interval is z=2.58.

The difference between means is

$\Delta M=M_v-M_o=5.10-5.55=-0.45$

Then the confidence interval can be constructed as

$\Delta M-z*s_{Md}\leq\mu_v-\mu_o\leq \Delta M+z*s_{Md}\\\\ -0.45-2.58*1.623\leq\mu_v-\mu_o\leq -0.450+2.58*1.623\\\\-0.450-4.187\leq\mu_v-\mu_o\leq-0.450+4.187\\\\-4.637\leq\mu_v-\mu_o\leq 3.737$

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3 years ago

Solve the inequality 2-x<7

dedylja [7]

Answer:

x > -5

Step-by-step explanation:

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