The x-coordinate of the point in quadrant III where f(x) = g(x) is -7
<h3>How to determine the x-coordinate in quadrant III?</h3>
The figure is not attached to the question; however, the question can still be solved
The quadratic function is given as:
f(x) = -(x +2)² + 17
The linear function passes through (0,-1) and (1,0).
So, we calculate the linear equation using:
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Substitute known values
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Evaluate
y = x - 1
So, we have:
- Quadratic function: f(x) = (x +2)² + 17
- Linear function: g(x) = x - 1
Next, we plot the graph of both functions (see attachment)
From the attached graph, both functions meet in the quadrant III at (-7,-8)
Hence, the x-coordinate of the point in quadrant III where f(x) = g(x) is -7
<h3>Justify the solution in (a), algebraically </h3>
In (a), we have the solution to be:
(x,y) = (-7,-8)
Substitute -7 for x in f(x) and g(x)
f(-7) = -(-7 +2)² + 17 = -8
g(-7) = -7 - 1 = -8
See that:
f(-7) = g(-7) = -8 and it is located in the third quadrant.
Hence, the solution in (a) is true
Read more about equation at:
brainly.com/question/2972832
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