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3 years ago

15

Write and solve a real-world problem that represents the following one-variable inequality.

1 answer:

serg [7]3 years ago

7 0

Hello there! An example problem for this could be:
Emile is looking for a cell-phone plan. His two options are one that costs $40 up front, and costs $0.01 per text, represented by x. The second one is 15 dollars up front and costs $0.06 for each text message. Emile figures that for the first package he has to send 500 texts or more to make it less than the second one.

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c(1)=−20 c(n)=c(n−1)+10 Find the 2nd term in the sequence.

Bad White [126]

Answer:

-10 is the second term.

Step-by-step explanation:

After the first term each term is obtained from the previous one by adding 10.

c(1) = -20

so c(2) = -20 + 10

= -10.

3 0

2 years ago

Pls help I will award brainiest

diamong [38]

Answer:

189

Step-by-step explanation:

ratio is 8:9

multiply ratio by 21 to get 168:189

3 0

2 years ago

Anyone know the answer to this?

Kaylis [27]

I think its a

because the line segments connect each other.

3 0

3 years ago

K=5/9(F+459.67) solve for F in terms of K

Mila [183]

Answer:

F = 5.67503704

Step-by-step explanation:

K=5/9(F+459.67) K = 5/9F / 5/9 = 255.376667 / 5/9 = F = 5.67503704

5 0

2 years ago

5^(2x-1)+5^(x+1)=250<br> how do you solve?<br> thank you

zepelin [54]

Answer:

<em>x = 2</em>

Step-by-step explanation:

<u>Exponential Equations</u>

Solve:

$5^{2x-1}+5^{x+1}=250$

Separate each exponential:

$5^{2x}5^{-1}+5^{x}5^{1}=250$

Operating:

$\displaystyle \frac{5^{2x}}{5}+5^{x}5=250$

Multiplying by 5:

$5^{2x}+25\cdot5^x=1250$

Rearranging:

$5^{2x}+25\cdot5^x-1250=0$

Recall that:

$5^{2x}=(5^{x})^2$

$(5^{x})^2+25\cdot5^x-1250=0$

Calling

$y=5^{x}:$

$y^2+25y-1250=0$

Factoring:

$(y-25)(y+50)=0$

There are two possible solutions:

y=25

y=-50

Since

$y=5^{x}$

y cannot be negative, thus:

$5^{x}=25=5^2$

The solution is:

x = 2

8 0

3 years ago