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Bas_tet [7]
3 years ago
11

What is the range of first 4 even numbers greater than 7?

Mathematics
1 answer:
Ksju [112]3 years ago
3 0

Answer:

The range consists of only one element, the number 8

Range = {8}

Step-by-step explanation:

Notice that the relationship requires as domain the first 4 even numbers.

That is, the numbers 2, 4, 6, and 8

Domain = {2, 4, 6, 8}

the relationship requires those numbers of the domain that are larger than 7.

There is clearly only one number that satisfies such relationship. Therefore, the only element of the Range is the number "8".

Range = {8}

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Use factoring to simplify the expression x^2-x-6/x-3 assume that x does not equal 3
Gre4nikov [31]
This works out beautifully.  You COULD use long division here, but since your numerator is a quadratic, your first instinct should be to try and factor it.  If you factor it, it works out to be (x - 3)(x + 2).  Now it just so happens that when you do that, the (x - 3) in the numerator will cancel with the (x - 3) in the denominator leaving you with one sad and lonely (x + 2) as your answer.
3 0
3 years ago
Oof this is probably really simple to most of y'all but I'm out of it.
Lelechka [254]

Answers:

  • angle1 = 156 degrees
  • angle2 = 24 degrees

=======================================================

Explanation:

The two angles form a straight line, which is 180 degrees

Add up the angle expressions and set the sum equal to 180.

(angle1) + (angle2) = 180

(4x) + (x-15) = 180

(4x+x)-15 = 180

5x-15 = 180

5x = 180+15

5x = 195

x = 195/5

x = 39

We use that x value to find each missing angle

  • angle1 = 4x = 4*39 = 156 degrees
  • angle2 = x-15 = 39-15 = 24 degrees

Then notice how angle1+angle2 = 156+24 = 180 to verify the answer.

Side note: Angles that add to 180 are considered supplementary.

6 0
2 years ago
Please help, i will give brainilest.
Maksim231197 [3]

Answer:

-36

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
How to do this question plz answer ​
harina [27]

9514 1404 393

Answer:

  300

Step-by-step explanation:

There are 25 ways to select the first student. After that student is removed from the selection pool for the second student, there are 24 ways to select the second student. This gives 25·24 = 600 ways to select 2 students <em>in a particular order</em>.

Since we don't care about the order, we can divide this number by the number of ways two students can be ordered: AB or BA, 2 ways.

  600/2 = 300

There are 300 ways to pick a combination of two students from 25.

__

<em>Additional comments</em>

This sort of selection (2 out of 25) has a formula for it, and an abbreviation for the formula.

 "n choose k" can be written nCk or C(n, k)

The function is a ratio of factorials:

  nCk = n!/(k!(n-k)!)

If you can typeset this, it is written ...

  \displaystyle\binom{n}{k}=\frac{n!}{k!\cdot(n-k)!}

This is different from the formula for the number of <em>permutations</em> of n things taken k at a time. That would be written nPk or P(n, k) = n!/(n-k)!.

5 0
2 years ago
Read 2 more answers
What is the LCM of 5,9,6,10
astraxan [27]

Answer:

1

1 is the only integer that can go into 5 as 5 is a prime number

7 0
2 years ago
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