All categories

3 years ago

Given the following Kb values, which cation is the strongest acid?

Chemistry

1 answer:

lions [1.4K]3 years ago

6 0

Answer:

The correct option is E

Explanation:

Generally the a base with the highest $K_b$ is the strongest base and from the data given

$C_2H_5NH_2$ has the highest value of $K_b$ so $C_2H_5NH_2$ is the strongest base while $(NH_2)_2CO$ has the lowest value of $K_b$ so $(NH_2)_2CO$ is the weakest base

Generally the conjugate acid of a weak base is always a strong acid

For $(NH_2)_2CO$ which the weakest base it conjugate acid which is $[NH_2NH_3CO]^+$ will be the strongest acid

You might be interested in

Please help!

lord [1]

Answer:

$\large \boxed{\text{6 L}}$

Explanation:

We can use Gay-Lussac's Law of Combining Volumes to solve this problem.

Gases at the same temperature and pressure react in the same ratios as their coefficients in the balanced equation.

1. Write the chemical equation.

Ratio: 1 L 3 L

N₂ + 3H₂ ⟶ 2NH₃

V/L: 2

2. Calculate the volume of H₂.

According to Gay-Lussac, 3 L of H₂ react with 1 L of N₂.

Then, the conversion factor is (3 L H₂/1 L N₂).

$\text{Volume of H}_{2} = \text{2 L N}_{2} \times \dfrac{ \text{3 L H}_{2} }{\text{1 L N}_{2}}= \textbf{6 L H}_{2}\\\text{You need $\large \boxed{\textbf{6 L}}$ of hydrogen,}$

8 0

4 years ago

What mass of NH3 in grams must be used to produce 1.81 tons of HNO3 by the Ostwald process, assuming an 80.0 percent yield in ea

Alex17521 [72]

The three reactions involved in the Ostwald process for the conversion of NH3 to HNO3 are:

4NH3(g) + 5O2(g) ==> 4NO(g) + 6H2O(l) ------(1)

2NO(g) + O2(g) ==> 2NO2(g) ------------------------(2)

3NO2(g) + H2O(l) ==> 2HNO3(aq) + NO(g) ---(3)

Mass of HNO3 produced = 1.81 tons

In grams, the mass of HNO3 = 1.81*2000*453.6 = 1642032 g

Molar mass of HNO3 = 63 g/mol

Thus, # moles of HNO3 produced = 1642032/63 = 26064 moles

Based on the stoichiometry of reaction (3):

Theoretical moles of NO2 = 1.5(Moles HNO2 ) = 1.5(26064) = 39096

Assuming 80% yield:

Actual moles of NO2 = 0.8*39096 = 31277 moles

Based on the stoichiometry in reaction (2):

Theoretical moles of NO = 31277 moles

Assuming 80% yield:

Actual moles of NO = 0.8*31277 = 25022 moles

Bases on stoichiometry in reaction(3):

Moles of NH3 = 25022 moles

Assuming 80% yield:

Actual moles of NH3 required = 0.8*25022 = 20018 moles

Mass of NH3 required = 20018 moles * 17 g/mole = 340306 g = 340.31 kg

7 0

4 years ago

Read 2 more answers

A chemist wishes to perform the following reaction: N2 + 3 H2 → 2 NH3 If only 14.0 g of N2 is available, what is the minimum amo

djyliett [7]

Answer:

3 grams

Explanation:

14 g of N2 is 1/2 mole

If you halve the N2 in the balanced equation , you have to halve the H2 down to 1.5 moles of H2 which is 3 grams

4 0

2 years ago

What is urine made of?

Annette [7]

Answer: 90 percent water, electrolytes such as potassium and phosphorus, and chemicals called urea and uric acid

Explanation:

6 0

3 years ago

How many moles are present in 63.80L of oxygen gas, O2?

matrenka [14]

Answer:

2.85moles of oxygen gas

Explanation:

Given parameters:

Volume of oxygen gas = 63.8L

Unknown:

Number of moles = ?

Solution:

We assume that the gas is under standard temperature and pressure. To find the number of moles, use the expression below:

1 mole of a gas at STP occupies a volume of 22.4L

So;

63.8L of oxygen gas will take up a volume of

$\frac{63.8}{22.4}$ = 2.85moles of oxygen gas

4 0

3 years ago