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2 years ago

How many moles are present in 63.80L of oxygen gas, O2?

Chemistry

1 answer:

matrenka [14]2 years ago

4 0

Answer:

2.85moles of oxygen gas

Explanation:

Given parameters:

Volume of oxygen gas = 63.8L

Unknown:

Number of moles = ?

Solution:

We assume that the gas is under standard temperature and pressure. To find the number of moles, use the expression below:

1 mole of a gas at STP occupies a volume of 22.4L

So;

63.8L of oxygen gas will take up a volume of

$\frac{63.8}{22.4}$ = 2.85moles of oxygen gas

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What is the volume of 40.0 grams of argon gas at STP ?

MrRa [10]

Answer:

24.9 L Ar

General Formulas and Concepts:

Atomic Structure

Reading a Periodic Table
Moles
STP (Standard Conditions for Temperature and Pressure) = 22.4 L per mole at 1 atm, 273 K

Aqueous Solutions

States of Matter

Stoichiometry

Using Dimensional Analysis

Explanation:

Step 1: Define

[Given] 40.0 g Ar

[Solve] L Ar

Step 2: Identify Conversions

[PT] Molar Mass of Ar - 39.95 g/mol

[STP] 22.4 L = 1 mol

Step 3: Convert

[DA] Set up: $\displaystyle 40.0 \ g \ Ar(\frac{1 \ mol \ Ar}{39.95 \ g \ Ar})(\frac{22.4 \ L \ Ar}{1 \ mol \ Ar})$
[DA] Divide/Multiply [Cancel out units]: $\displaystyle 24.9235 \ L \ Ar$

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

24.9235 L Ar ≈ 24.9 L Ar

5 0

2 years ago

Having been heated to 800 K , at some point the tank starts to leak. By the time the leak is repaired, the tank contains only ha

Liula [17]

Answer: The temperature of the gas reduced to 400K.

Explanation:

Stated that ; The pressure remains the same, that is initial and final pressure equals 1atm.

Applying Charles Law

$V1/T1 = V2/T2$

Initial volume V1 = 1

Final volume V2 = 1/2 (halved)

Initial temperature T1 =800K

Final temperature T2 = ?

(1/800) = (1/2)/T2

T2 = 800/2

T= 400K

Therefore, when the volume is halved, the temperature reduced also to half ( 400K)

3 0

2 years ago

Based on what basis the elements had been arranged

salantis [7]

Answer:

The increase in the atomic number

6 0

2 years ago

What is the difference between a mixture and compound?

rewona [7]

Compound: a thing that is composed of two or more separate elements, basically it is a mixture

Mixture: a substance made by mixing other substances together

so go from there. I don't want to cheat by giving answers, so I hope this is guiding and helpful. please mark brainliest if it is!

4 0

3 years ago

A sample of gas contains 0.1800 mol of CO(g) and 0.1800 mol of NO(g) and occupies a volume of 23.2 L. The following reaction tak

baherus [9]

Answer:

The volume of the sample is 17.4L

Explanation:

The reaction that occurs requires the same amount of CO and NO. As the moles added of both reactants are the same you don't have any limiting reactant. The only thing we need is the reaction where 4 moles of gases (2mol CO + 2mol NO) produce 3 moles of gases (2mol CO2 + 1mol N2). The moles produced are:

0.1800mol + 0.1800mol reactants =

0.3600mol reactant * (3mol products / 4mol reactants) = 0.2700 moles products.

Using Avogadro's law (States the moles of a gas are directly proportional to its pressure under constant temperature and pressure) we can find the volume of the products:

V1n2 = V2n1

Where V is volume and n moles of 1, initial state and 2, final state of the gas

Replacing:

V1 = 23.2L

n2 = 0.2700 moles

V2 = ??

n1 = 0.3600 moles

23.2L*0.2700mol = V2*0.3600moles

17.4L = V2

<h3>The volume of the sample is 17.4L</h3>

8 0

2 years ago