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netineya [11]
2 years ago
12

How many moles are present in 63.80L of oxygen gas, O2?

Chemistry
1 answer:
matrenka [14]2 years ago
4 0

Answer:

2.85moles of oxygen gas

Explanation:

Given parameters:

Volume of oxygen gas  = 63.8L

Unknown:

Number of moles  = ?

Solution:

We assume that the gas is under standard temperature and pressure. To find the number of moles, use the expression below:

     1 mole of a gas at STP occupies a volume of 22.4L

 So;

       63.8L of oxygen gas will take up a volume of

              \frac{63.8}{22.4}   = 2.85moles of oxygen gas

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Answer:

Gold is a metal, more specifically a transition metal, whereas Oxygen is a nonmetal, more specifically a reactive nonmetal. Using this information, you can compare and contrast metals, nonmetals, and metalloids.

Metals are:

Shiny

High melting point

Mostly silver or gray in color

Mostly solids at room temperature – Mercury (Hg) is a liquid at room temperature

Malleable – able to be hammered into a thin sheet

Ductile – able to be drawn/pulled into a wire

Good conductors of heat and electricity

Nonmetals are:

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Brittle – break easily

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Not ductile

Poor conductors of heat and electricity

Metalloids are:

Found on the “zig-zag” line on the Periodic Table of Elements

Have properties of both metals and nonmetals

Can be shiny or dull

Semiconductors – able to conduct electricity under certain conditions

Explanation:

Reccomend this site for questions llike these: https://ptable.com/#Properties

7 0
3 years ago
How long does it take the sun to melt a block of ice at 0∘c with a flat horizontal area 1.0 m2 and thickness 1.8 cm ? assume tha
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This is a problem involving heat transfer through radiation. The solution to this problem would be to use the formula for heat flux.

ΔQ/Δt = (1000 W/m²)∈Acosθ

A is the total surface area:
A = (1 m²) + 4(1.8 cm)(1m/100 cm)(√(1 m²))
A = 1.072 m²

ΔQ is the heat of melting ice.
ΔQ = mΔHfus
Let's find its mass knowing that the density of ice is 916.7 kg/m³.
ΔQ = (916.7 kg/m³)(1 m²)(1.8 cm)(1m/100 cm)(<span>333,550 J/kg)
</span>ΔQ = 5,503,780 J

5,503,780 J/Δt = (1000 W/m²)(0.05)(1.072 m²)(cos 33°)
<em>Δt = 122,434.691 s or 34 hours</em>

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a sample of substance x that has a mass of 326.0 g releases 4325.8 cal when it freezes at its freezing point. if substance x has
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1) Calculate the number of mols,n,  of the substance

n = mass/ molar mass = 326.0 g / 58.45 g / mol = 5.577 moles

2) Calculate the molar heat of fusion as the total heat released by the sample divided by the number of moles

hf = heat released / n = 4325.8 cal / 5.577 moles = 775. 59 cal /mol
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