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Oxana [17]
3 years ago
9

Write the rule of the transformation

Mathematics
1 answer:
Ratling [72]3 years ago
3 0

Answer:

(x + 5, y + 1)

Step-by-step explanation:

As we can see, what we have is a translation

let us pick a point

G( -5,-2)

To;

G’(0,-1)

so the shift on the x-axis is;

(0-(-5)) = 5

shift on the y-axis is;

(-1-(-2) = 1

we have a rightward shift of 5 units on the x-axis and 1 unit on the y-axis

So we have the rule as;

(x + 5, y + 1)

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Explanation:

Look at the graph and add up all of the numbers. Hope this helps!

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2.5∙0.04∙250∙8∙1.25∙789
Xelga [282]

Answer:

197,250

Step-by-step explanation:

2.5 * 0.04 * 250 * 8 * 1.25 * 789

0.1 * 250 * 8 * 1.25 * 789

25 * 8 * 1.25 * 789

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Krutika rolls a fair dice 18 times.<br> How many times would Krutika expect to roll a four?
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Step-by-step explanation:

4 0
3 years ago
What is [[3^3-7)·5)/10]+((1+3+6+9)-)]
yanalaym [24]

Answer:

\left(\left(3^3-7\right)\frac{5}{10}\right)+\left(\left(1+3+6+9\right)-1\right)=28

Step-by-step explanation:

As far as I am able to observe from the statement of your question, the expression is:

\left[[\left(3^3-7\right)\cdot \frac{5}{10}\right]+\left(\left(1+3+6+9\right)-1\right)

So, lets solve this expression, which anyways would clear your concept

Considering the expression

\left[[\left(3^3-7\right)\cdot \frac{5}{10}\right]+\left(\left(1+3+6+9\right)-1\right)

\mathrm{Remove\:parentheses}:\quad \left(a\right)=a

=\left(3^3-7\right)\frac{5}{10}+1+3+6+9-1

Lets first solve \left(3^3-7\right)\frac{5}{10}

As 3^3=27

=\frac{5}{10}\left(27-7\right)

=\frac{1}{2}\left(27-7\right)

=20\cdot \frac{1}{2}

=10

So,

\left(3^3-7\right)\frac{5}{10}+1+3+6+9-1 = 10+1+3+6+9-1  

                                                 =  28

Therefore,

\left(\left(3^3-7\right)\frac{5}{10}\right)+\left(\left(1+3+6+9\right)-1\right)=28

Keywords: Expression solving

Learn more about solving expression from brainly.com/question/4687406

#learnwithBrainly

7 0
3 years ago
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