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ddd [48]
3 years ago
5

Which? A B C D Help me for 20 points!!!

Mathematics
1 answer:
Alekssandra [29.7K]3 years ago
3 0
B, 7 3/10 minus 5 7/10 is 1 6/10
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Mr. Nicholas invested $4,250 into an account that pays 3.5% interest, compounded annually. How much will Mr. Nicholas’s investme
Lina20 [59]

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$5596.44

Step-by-step explanation:

$4250*(1.035)^8= $5596.44

3 0
3 years ago
10.
Hatshy [7]

Answer:

15

Step-by-step explanation:

4 (Book per cost)+ 4.47 (Shipping Fee) = 8.75 cost of one book $132.75 Divided by $8.75 = 15 Books bought.

7 0
3 years ago
PLEASE HELP ME OUT...
katrin2010 [14]

Answer:

area = 144\pi

Step-by-step explanation:

volume =  \frac{4}{3} \pi {r}^{3}  \\  \\ 288\pi =  \frac{4}{3} \pi {r}^{3} \\  \\ 3(288\pi) = 4\pi {r}^{3} \\  \\  \frac{3(288\pi)}{4\pi}  =  {r}^{3}  \\  \\ 216 =  {r}^{3}  \\  \\ r =  \sqrt[3]{216}  \\ r = 6

area = 4\pi {r}^{2}  \\ area = 4\pi ({6}^{2})  \\ area = 144\pi

7 0
3 years ago
In the image below, ABC ~ DEF What is the length of EF and the measure of D
Gwar [14]
If triangle ABC is congruent to triangle DEF, then EF = BC = 27
This is because BC and EF are the last two letters of ABC and DEF respectively. They match up and correspond, being congruent by CPCTC

-------------------------------------------------------------------------------------------------------------

Similarly, if triangle ABC is congruent to triangle DEF, then angle D = angle A = 49 degrees

The letter D and the letter A are the first letters of DEF and ABC respectively. So they match up and are congruent by CPCTC

CPCTC = Corresponding Parts of Congruent Triangles are Congruent

-------------------------------------------------------------------------------------------------------------

So in short, the answer is choice B) 27; 49

7 0
3 years ago
In a figure, OB is the radius of a big semicircle and XB is the radius of the small semicircle. Given that OX = 14 cm, Calculate
oee [108]

Answer:

perimeter of the shaded region = 88 +44+28 =160 cm

Step-by-step explanation:

perimeter of shaded region = length AO + arc OB + arc AB

length AO = radius of bigger circle

radius of bigger circle = OX + OB = 2×radius of smaller circle = 2×14 cm = 28 cm

therefore AO = 28 cm

length of arc oB= half of circumference of smaller circle = \pi×14 = 44 cm

length of arc ab = half of circumference of bigger circle  = \pi×28 =\frac{22}{7}×28= 88

therefore perimeter of the shaded region = 88 +44+28 =160 cm

area of the shaded region = half of area of bigger circle - half of area of smaller circle

                                           =\frac{1}{2} \pi 28^{2} -\frac{1}{2} \pi 14^{2}

                                           =\frac{\pi }{2} (28^{2} -14^{2} )

  solving we gen area of shaded region = 924

7 0
3 years ago
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