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Tpy6a [65]
3 years ago
15

There are 200 students in the 8th grade class at Alleghany Middle School. Of these students, 8% play basketball and 14% play soc

cer. Six students play on both teams. What is the probability that a student plays either basketball or soccer?
Mathematics
1 answer:
sergeinik [125]3 years ago
6 0

Answer:

The probability that a student plays either basketball or soccer is 19% or 0.19.

Step-by-step explanation:

Let A be the event that student play basketball and  B be the event that student play soccer.

P(A)=8\%

P(B)=14\%

It is given that 6 students play on both teams.

P(A\cap B)=\frac{6}{200}\times 100=3\%

We have to find the probability that a student plays either basketball or soccer.

P(A\cup B)=P(A)+P(B)-(A\cap B)

P(A\cup B)=8\%+14\%-3\%

P(A\cup B)=19\%

Therefore the probability that a student plays either basketball or soccer is 19% or 0.19.

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Answer:

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Step-by-step explanation:

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4 0
3 years ago
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Ahmad run 5 kilometres. If he completed 15% of the race. How many kilometres is the race?
stepladder [879]

Answer:

x = 33.33 kilometers

Step-by-step explanation:

you could make use of the percent, base, and rate formula here. we know that 15% is the rate, 5 kilometers is the percent, therefore what we are looking for is our base.

\frac{percent}{base} =\frac{rate}{100}

\frac{5}{x}=\frac{15}{100} ; cross multiply.

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therefore, the race is 33.33 kilometers.

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3 years ago
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Step-by-step explanation:

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3 years ago
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Answer:

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Step-by-step explanation:

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3 years ago
Simplify, 99/121 whats the GCF?
Nadya [2.5K]

To find the GCF:

-- List the factors of the first number.
-- List the factors of the second number.
-- Make a short list of the factors that show up for BOTH numbers.
-- Find the biggest number on the short list.

Factors of the first number (99):  <u>1</u>, 3, 9, <u>11</u>, 33, 99 .

Factors of the second number (121):  <u>1</u>, <u>11</u>, 121 .

Short list (factors that show up for both numbers):  1, 11

Biggest number on the short list:  <em>11</em>


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