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Tpy6a [65]
3 years ago
15

There are 200 students in the 8th grade class at Alleghany Middle School. Of these students, 8% play basketball and 14% play soc

cer. Six students play on both teams. What is the probability that a student plays either basketball or soccer?
Mathematics
1 answer:
sergeinik [125]3 years ago
6 0

Answer:

The probability that a student plays either basketball or soccer is 19% or 0.19.

Step-by-step explanation:

Let A be the event that student play basketball and  B be the event that student play soccer.

P(A)=8\%

P(B)=14\%

It is given that 6 students play on both teams.

P(A\cap B)=\frac{6}{200}\times 100=3\%

We have to find the probability that a student plays either basketball or soccer.

P(A\cup B)=P(A)+P(B)-(A\cap B)

P(A\cup B)=8\%+14\%-3\%

P(A\cup B)=19\%

Therefore the probability that a student plays either basketball or soccer is 19% or 0.19.

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Answer:

0.150,0.595

Step-by-step explanation:

Given that at a self-service gas station, 40% of customers pump regular gas, 35% pump midgrade, and 25% pump premium gas. Of those who pump regular, 30% pay at least $30. Of those who pump midgrade, 50% pay at least $30. And of those who pump premium, 60% pay at least $30.

               Regular gas          Midgrade         Premium gas      Total

Percent      40                            35                     25                   100

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a) The   probability that the next customer pumps premium gas and pays at least $30

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b)        the probability that the next customer pays at least $30

= P(regular and pays atleast 30%)+P(premium and pays atleast 30%)+P(midgrade and       pays atleast 30%)

=0.40*0.30+0.35*0.50+0.25*0.60\\=0.12+0.175+0.30\\=0.595                  

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