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Tpy6a [65]
4 years ago
15

There are 200 students in the 8th grade class at Alleghany Middle School. Of these students, 8% play basketball and 14% play soc

cer. Six students play on both teams. What is the probability that a student plays either basketball or soccer?
Mathematics
1 answer:
sergeinik [125]4 years ago
6 0

Answer:

The probability that a student plays either basketball or soccer is 19% or 0.19.

Step-by-step explanation:

Let A be the event that student play basketball and  B be the event that student play soccer.

P(A)=8\%

P(B)=14\%

It is given that 6 students play on both teams.

P(A\cap B)=\frac{6}{200}\times 100=3\%

We have to find the probability that a student plays either basketball or soccer.

P(A\cup B)=P(A)+P(B)-(A\cap B)

P(A\cup B)=8\%+14\%-3\%

P(A\cup B)=19\%

Therefore the probability that a student plays either basketball or soccer is 19% or 0.19.

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Can someone pls help, I know this is kind of a lot but I’ve been stuck on this for a while now.
Greeley [361]

9514 1404 393

Answer:

  (a, b, c) = (-0.425595, 11.7321, 2.16667)

  f(x) = -0.425595x² +11.7321x +2.16667

  f(1) ≈ 13.5

Step-by-step explanation:

A suitable tool makes short work of this. Most spreadsheets and graphing calculators will do quadratic regression. All you have to do is enter the data and make use of the appropriate built-in functions.

Desmos will do least-squares fitting of almost any function you want to use as a model. It tells you ...

  a = -0.425595

  b = 11.7321

  c = 2.16667

so

  f(x) = -0.425595x² +11.7321x +2.16667

and f(1) ≈ 13.5

_____

<em>Additional comment</em>

Note that a quadratic function doesn't model the data very well if you're trying to extrapolate to times outside the original domain.

3 0
3 years ago
A.Calculate the mean,median and mode.(3 points each) 1.)1,2,3,4,5 2.)2,3,4,5,6,6 3.)6,7,5,4,5,6,2,5
zlopas [31]

Answer:

Step-by-step explanation:

1.)1,2,3,4,5

mean=sum of all values/number of values

         =1+2+3+4+5/5

         =15/5

mean=3

Mode :

In the given data, no observation occurs more than once.

Hence the mode of the observations does not exist, means mode=0.

Median

1,2,3,4,5

Middle value is 3 so the median is 3.

2.)2,3,4,5,6,6

mean=sum of all values/number of values

         =2+3+4+5+6+6/6

         =26/6

mean =4.33

Mode

      is that value of the observation which occurs maximum number of times so here mode is 6.

Median

2,3,4,5,6,6

 4+5/2

9/2

median=4.5

3.)6,7,5,4,5,6,2,5

mean=sum of all values/number of values

         =6+7+5+4+5+6+2+5/8

        =40/8

mean =5

Mode

is that value of the observation which occurs maximum number of times so here mode is 5

Median

2,4,5,5,5,6,6,7

5+5/2

10/2

median=5

 

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3 years ago
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Answer:

A does not have any proportional relationship.

Step-by-step explanation:

All of the other tables have obvious relationships, leaving A to be the answer.

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