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dezoksy [38]
3 years ago
6

A circle has a diameter of 20 inches and a central angle AOB that measures 160°. What is the length of the intercepted arc AB? U

se 3.14 for pi and round your answer to the nearest tenth.
Mathematics
1 answer:
juin [17]3 years ago
5 0
Calculate the circumference of the full circle:

circumference = PI x diameter = 3.14 x 20 = 62.8 inches
 the arc length is 160 degrees of the full circle

divide 160 by 360 (full circle) and multiply by the circumference:

160/360 x 62.8 = 27.9 inches

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2 years ago
A rectangle has length 72 cm and width 56 cm. The other rectangle has the same area as this one, but its width is 21 cm. What is
katovenus [111]

Answer:

The constant of variation is 4032

Step-by-step explanation:

Given:  

Let a rectangle (say A) has length of rectangle(l)= 72 cm and width of rectangle(w) = 56 cm.

Area of rectangle is multiply its length by its width.

Then,

area of rectangle (A) =l \times w = 72 \times 56 = 4,032 square cm.

It is given that the other rectangle B has the same area as the rectangle A.

Then, the area of rectangle (B) = area of rectangle (A) = 4,032 square cm.  .......[1]

First find the length of rectangle B:

Given: width of the rectangle B is 21 cm

then, by definition

Area of rectangle B = l \times w = l \times 21

From [1];

4032 = l \times 21

Divide 21 both sides we get;

l =\frac{4032}{21} = 192 cm

therefore, the length of rectangle B is 192 cm

To find the constant variation:

if y varies inversely as x

i.e, y \propto \frac{1}{x}

⇒ y = \frac{k}{x} where k is the constant variation.

or k = xy

As area of rectangle is multiply its length by width.

This is the inversely variation.

as: l \propto \frac{1}{w}

or l = \frac{A}{w} where A is the constant of variation

Since, the area (A) of both the rectangles are constant.

therefore, the constant of variation is, 4032


5 0
3 years ago
LOL Needing help im not very smart XD
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12 because it’s 12 :)))))
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