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3 years ago

13

Can two fractions with the same numerator and different denominators can be equal.

1 answer:

mel-nik [20]3 years ago

8 0

Nope!

They cannot be equal if they have the same numerator but different denominators. they need to be able to reduce into the same number

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Simplify the equation -2(p + 4)2 - 3 + 5p. What is the simplified expression in standard form? ASAP PLEASE!! ILL GIVE EXTRA POIN

Katena32 [7]

So you distrubute and get

-2p-8+2-3+5p
add like terms
3p-9
ANSWER: 3p-9

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Round 0.248 to nearest tenth.

kupik [55]

0.248 rounded to the nearest tenth is 0.2 because 4 comes after and if there is a number after the number that you are rounding that is less than 5, you keep the number and do not change it.

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What is the difference between an irrational number and an integer?? please explain!

SpyIntel [72]

Answer:

Explanation: Irrational numbers are non-terminating, recurring decimal numbers i.e, a decimal expansion that neither terminates nor becomes periodic which cannot be expressed in the form of a fraction. ... Integer is a complete entity that includes every natural number along with its negatives and zero.

Step-by-step explanation:

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3 years ago

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Divide x4+2x2−24<br> by x+2

Ipatiy [6.2K]

$\begin{array}{c|c}_{-}\ x^4+2x^2-24 &\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\! \underline{ x+2 } \\ \!\!\!\!\!\!\!\!\!\!\! \underline{x^4+2x^3}& x^3-2x^2+4x-8 \\{ \big{_{-}}}-2x^3-24& \\\underline{-2x^3-4x^2}& \\ _{-} \ 4x^2-24 & \\ \underline{4x^2+8x}& \\ _{-}-8x-24& \\ \underline{-8x-16} & \\ -8 &\end {array }$

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3 years ago

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Q5: The probability that event A occurs is 5/7 and the probability that event B occurs is 2/3 . If A and B are independent event

bekas [8.4K]

Answer:

$P(A \cap B)$

And we can use the following formula:

$P(A \cap B)= P(A)* P(B)$

And replacing the info we got:

$P(A \cap B) = \frac{5}{7} \frac{2}{3}= \frac{10}{21}=0.476$

Step-by-step explanation:

We define two events for this case A and B. And we know the probability for each individual event given by the problem:

$p(A) = \frac{5}{7}$

$p(B) = \frac{2}{3}$

And we want to find the probability that A and B both occurs if A and B are independent events, who menas the following conditions:

$P(A|B) = P(A)$

$P(B|A) = P(B)$

And for this special case we want to find this probability:

$P(A \cap B)$

And we can use the following formula:

$P(A \cap B)= P(A)* P(B)$

And replacing the info we got:

$P(A \cap B) = \frac{5}{7} \frac{2}{3}= \frac{10}{21}=0.476$

7 0

3 years ago