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3 years ago

15

Anybody get this??? please help.

1 answer:

lbvjy [14]3 years ago

6 0

Hey there! "

Firstly we have to combine your like terms

Like: $2x \\ and \\ 5x \\ \\ \\ 0 \\ and \\ 0$

Out of all of those terms we get

$2x= 5x$

Out of those terms we just did, ( $2x \\ and \\ 5x$ ) , we have to move on to your next step which is to $subtract$ by $5x$ on each of your sides

Like: $2x- 5x \\ \\ = 5x -5x$

Cancel: $5x - 5x$ because it give you the result of $0$

Keep: $2x - 5x$ because it is helping you solve for your actual answer!

$2x - 5x = -3 \\ \\ -3 = 0$

Now we have to $divide$ by $-3$ on each of your sides

Like: $\frac{-3x}{3} = \frac{0}{-3}$

Cancel: $\frac{-3x}{-3}$ because it gives you the result of a $1$

Keep: $\frac{0}{3 }$ because it gives you your result

Answer; $x = 0 , y = 0$

Good luck on your assignment and enjoy your day!

~ $LoveYourselfFirst:)$

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3 0

3 years ago

Read 2 more answers

The water from a fire hose follows a path described by y equals 2.0 plus 0.9 x minus 0.10 x squared (units are in meters). If

Alecsey [184]

Answer:

The resultant velocity is 12.21 m/s.

Step-by-step explanation:

We are given that the water from a fire hose follows a path described by y equals 2.0 plus 0.9 x minus 0.10 x squared (units are in meters).

Also, v Subscript x is constant at 10.0 m/s.

The water from a fire hose follows a path described by the following equation below;

$y=2.0 + 0.9x-0.10x^{2}$

The velocity of the $x$ component is constant at = $v_x=10.0 \text{ m/s}$

and the point at which resultant velocity has to be calculated is (9.0,2.0).

Let the velocity of x and y component be represented as;

$v_x=\frac{dx}{dt} \text{ and } v_y=\frac{dy}{dt}$

Now, differentiating the above equation with respect to t, we get;

$y=2.0 + 0.9x-0.10x^{2}$

$\frac{dy}{dt} =0 + 0.9\frac{dx}{dt} -(0.10\times 2)\frac{dx}{dt}$

$\frac{dy}{dt} = 0.9\frac{dx}{dt} -0.2\frac{dx}{dt}$

$v_y = 0.9v_x -0.2v_x$

$v_y = 0.7v_x$

Now, putting $v_x=10.0 \text{ m/s}$ in the above equation;

$v_y = 0.7 \times 10.0$ = 7 m/s

Now, the resultant velocity is given by = $v=\sqrt{v_x^{2}+v_y^{2} }$

$v=\sqrt{10^{2}+7^{2} }$

= $\sqrt{149}$ = 12.21 m/s

5 0

3 years ago