Answer:
Option B, Rr pp × rr Pp
Explanation:
Given
Walnut Comb is produces when one dominant allele R is present at one gene locus and at least one dominant allele P is present at a second gene locus - R* P*
Rose Comb - at least one dominant allele is present at the first locus and two recessive alleles are present at the second locus - R* pp
Pea comb - two recessive alleles are present at the first locus and at least one dominant allele is present at the second - rr P*
Single comb - two recessive alleles are present at the first and the second locus - rrpp
Parent are rose combed and pea combed
For being rose genotype must be R* pp
and for being pea combed genotype must be rr P*
Rr pp x rr Pp
will produce
Walnut comb with genotype Rr Pp
Single comb with genotype rrpp
and pea comb with genotype rrPp
Hence, option B is correct
The answer would be proper strength since others do not make sense in detailed.
Answer:
1) M1 is heterozygous since it contains 2 bands, which means that it contains one recessive and one dominant allele
P1 is homozygous for this locus, since it contains a single band or is known to be homozygous for the locus or gene.
P2 is hetozygous for this locus because two bands appear in which each band represents one allele for the gene.
ChildC contains two gel bands, representing two alleles and is therefore heterozygous
P1 is the father of the child C1, if we look at the gel, each father shows a similar band, one coinciding with the mother and the second with the father p1
As for the paternity study, the PCR test is not useful, since it provides asymmetric results, thus only one strand information will be provided, and because the DNA is double-stranded, a more complete study is required.:
Answer:
Your answer is C) latitude.
