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abruzzese [7]
3 years ago
5

Folded mountains are formed

Physics
1 answer:
irga5000 [103]3 years ago
7 0
<span>at convergent boundaries</span>
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(b) The figure below shows a model train, travelling at speed , approaching a
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Answer:

0.62 m/s

Explanation:

Given that a model train, travelling at speed , approaching a buffer model train buffer spring

The train, of mass 2.5 kg, is stopped by compressing a spring in the buffer.

After the train has stopped, the energy stored in the spring is 0.48 J.

Calculate the initial speed v of the train

Solution

The total energy stored in the spring will be equal to the kinetic energy of the train.

That is,

1/2fe = 1/2mv^2

Substitutes the spring energy, and mass into the formula

0.48 = 1/2 × 2.5 × V^2

2.5V^2 = 0.96

V^2 = 0.96 / 2.5

V^2 = 0.384

V = sqrt ( 0.384 )

V = 0.62 m/s

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If a positive metal sphere touches a negative metal sphere what will happen?
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A neutral metal sphere is touched by a negatively charged metal rod. ... If a negative object is used to charge a neutral object, then both objects become charged negatively. In order for the neutral sphere to become negative, it must gain electrons from the negatively charged rod.
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The electron density in copper is 8.49 × 1028 electrons/m3. When a 1.00 A current is present in a copper wire with a 0.40 cm2 cr
vichka [17]

Answer:

Drift velocity in m/s is 1.84 \times 10^{-8}\ m/s.

Explanation:

<em>Formula for Drift Velocity is</em>:

u = \dfrac{I}{nAq}

Where I is the current

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A is the area of cross section and

q is the charge of one electron.

We are given the following:

n = 8.49 \times 10^{28}\ electrons/m^3

I = 1 A

A = 0.40 cm^2 = 40 \times 10^{-4} m^{2}

We know that q = 1.6\times10^{-19} C

Putting all the values to find drift velocity:

u = \dfrac{1}{8.49 \times 10 ^{28} \times 40 \times 10^{-4}\times 1.6 \times 10^{-19}}\\u = \dfrac{1}{543.36 \times 10 ^{5} }\\u = 1.84 \times 10^{-8}\ m/s

So, <em>drift velocity in m/s</em> is 1.84 \times 10^{-8}\ m/s.

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