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ehidna [41]
3 years ago
8

The centripetal force depends on the mass of body, angular velocity and radius of circular path. Find the expression for the cen

tripetal force. ​
Physics
1 answer:
vitfil [10]3 years ago
5 0

Answer:

F = m ω² r

Explanation:

Centripetal force is mass times centripetal acceleration:

F = ma

F = m v² / r

In terms of angular velocity:

F = m (ωr)² / r

F = m ω² r

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a 150 kg roller coaster is released from rest at the top of a 50 m hill. how fast will it be going if the second hill is 10 m hi
pav-90 [236]

Answer:

10 m/s

Explanation:

The potential energy of the roller coaster is converted to kinetic energy. According to law of transformation of energy, potential energy = kinetic energy.

mgh = ½mv².Take g as 10m/s².

150 * 10 * 50 = ½ * 150 * v².

7500 = 75v².

v² = 7500/75.

v = √100.

v= 10 m/s.

8 0
3 years ago
A man ties one end of a strong rope 8.17 m long to the bumper of his truck, 0.524 m from the ground, and the other end to a vert
Kamila [148]

Answer:

2442.5 Nm

Explanation:

Tension, T = 8.57 x 10^2 N

length of rope, l = 8.17 m

y = 0.524 m

h = 2.99 m

According to diagram

Sin θ = (2.99 - 0.524) / 8.17

Sin θ = 0.3018

θ = 17.6°

So, torque about the base of the tree is

Torque = T x Cos θ x 2.99

Torque = 8.57 x 100 x Cos 17.6° x 2.99

Torque = 2442.5 Nm

thus, the torque is 2442.5 Nm.

8 0
4 years ago
Which feature of a heating curve indicates a change of state
ziro4ka [17]

Answer:

The diagonal or the inclined lines shows the changes in terms of temperature, and the horizontal lines shows the changing of phases.

Explanation:

hope it is useful

3 0
3 years ago
تقطع اولا مسافة 8 km شمالا من البيت ثم تمشي شرقا حتى تكون ازاحتك من البيت 10km ما مقدار المسافة التي قطعتها شرقا
Natali [406]
He moved 2 km
I speak arabik ;)

8 0
3 years ago
An object starts from rest and accelerates uniformly in a straight line in the positive x direction. After 11 seconds, its speed
vladimir1956 [14]

Answer:

v_{avg}=35m/s

Explanation:

To calculate the average velocity we must know the distance traveled and do v_{avg}=\frac{d}{t}. The distance traveled is d=\frac{at^2}{2}, so we need to calculate the acceleration, which, since it's uniform, is a=\frac{\Delta v}{\Delta t}=\frac{v_f}{t}. Putting all together:

v_{avg}=\frac{d}{t}=\frac{at^2}{2t}=\frac{at}{2}=\frac{v_ft}{2t}=\frac{v_f}{2}=35m/s

4 0
3 years ago
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