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Nastasia [14]
3 years ago
7

Block A, with a mass of 6.0 kg, is sliding across a frictionless track at 65 m/s when it collides with Block B ( 9.0 kg) which i

s initially at rest . The two masses stick together and travel around a vertical loop with an unknown radius. They just barely make it around the vertical loop with an unknown radius.
a) Calculate the centrifugal force acting on the masses at the top of the loop
b) Calculate the velocity of the blocks just after the collision
c) Calculate the radius of the loop so that the blocks just barely make it
d) Calculate the normal force acting on the blocks when they reach the bottom after traveling through the loop
Physics
1 answer:
Mars2501 [29]3 years ago
3 0
The correct answer is a I hope that helped enjoy the rest of your weekend
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Light is an oscillating magnetic field alone. an oscillating electric field alone. electric and magnetic fields that oscillate p
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Explanation:

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An open 1-m-diameter tank contains water at a depth of 0.5 m when at rest. As the tank is rotated about its vertical axis the ce
Morgarella [4.7K]

Answer:

Angular velocity (w) = 8.86 rad/s

Explanation:

Angular velocity (w) = \sqrt{} 4ghi/R^{2}

g= 9.81 m/s

R= 0.5

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Hence= \sqrt4* 9.81* 0.5/0.5^{2}  = 8.86 rad/s

3 0
3 years ago
The constant forces F1 = 8 + 29 + 32 N and F2 = 48 - 59 - 22 N act together on a particle during a displacement from the point A
steposvetlana [31]

Answer:

- 600 J

Explanation:

A (20, 15, 0 ) m

B (0, 0, 7) m

\overrightarrow{F_{1}}=8\widehat{i}+29\widehat{j}+32\widehat{k}

\overrightarrow{F_{2}}=48\widehat{i}-59\widehat{j}-22\widehat{k}

Net force

\overrightarrow{F}=\overrightarrow{F_{1}}+\overrightarrow{F_{2}}

\overrightarrow{F}}=\left ( 8+48 \right )\widehat{i}+\left ( 29-59 \right )\widehat{j}+\left ( 32-22 \right )\widehat{k}

\overrightarrow{F}}=56\widehat{i}-30\widehat{j}+10\widehat{k}

\overrightarrow{S}=\overrightarrow{OB}-\overrightarrow{OA}

\overrightarrow{S}=\left ( 0-20 \right )\widehat{i}+\left ( 0-15 \right )\widehat{j}+\left ( 7-0 \right )\widehat{k}

\overrightarrow{S}=-20\widehat{i}-15\widehat{j}+7\widehat{k}

Work done is defined as

W = \overrightarrow{F}.\overrightarrow{S}

W = \left ( 56\widehat{i}-30\widehat{j}+10\widehat{k} \right ).\left (-20\widehat{i}-15\widehat{j}+7\widehat{k}  \right )

W = -1120 + 450 + 70

W = - 600 J

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3 years ago
Out of aluminum,copper,steel,and glass.Which material do you think will be the best thermal conductor?
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