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Nastasia [14]
3 years ago
7

Block A, with a mass of 6.0 kg, is sliding across a frictionless track at 65 m/s when it collides with Block B ( 9.0 kg) which i

s initially at rest . The two masses stick together and travel around a vertical loop with an unknown radius. They just barely make it around the vertical loop with an unknown radius.
a) Calculate the centrifugal force acting on the masses at the top of the loop
b) Calculate the velocity of the blocks just after the collision
c) Calculate the radius of the loop so that the blocks just barely make it
d) Calculate the normal force acting on the blocks when they reach the bottom after traveling through the loop
Physics
1 answer:
Mars2501 [29]3 years ago
3 0
The correct answer is a I hope that helped enjoy the rest of your weekend
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The earth's liquid outer core is the major cause of the earth’s magnetic field.

<h3>What is magnetic field?</h3>

The magnetic influence on moving electric charges, electric currents, and magnetic materials is described by a magnetic field, a vector field. A force acting on a charge while it travels through a magnetic field is perpendicular to both the charge's motion and the magnetic field. The magnetic field of a permanent magnet attracts or repels other magnets as well as ferromagnetic elements like iron. A magnetic field that varies with location will also exert a force on a variety of non-magnetic materials by changing the velocity of those particles' outer electrons. Electric currents, like those utilised in electromagnets, and electric fields that change over time produce magnetic fields that surround magnetised things.

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tekilochka [14]
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Can someone please help me with this question? ASAP thank you!
Assoli18 [71]

did you get the answer

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3 years ago
Mr.smith and his wife were trying to move their new chair. Mr. Smith pulls with a force of 30N while Mrs.Smith pushes with a for
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A steel rod is pulled in tension with a stress that is less than the yield strength. The modulus of elasticity may be calculated
pshichka [43]

Answer:

B. Axial stress divided by axial strain

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Yield strength:

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