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Nastasia [14]
3 years ago
7

Block A, with a mass of 6.0 kg, is sliding across a frictionless track at 65 m/s when it collides with Block B ( 9.0 kg) which i

s initially at rest . The two masses stick together and travel around a vertical loop with an unknown radius. They just barely make it around the vertical loop with an unknown radius.
a) Calculate the centrifugal force acting on the masses at the top of the loop
b) Calculate the velocity of the blocks just after the collision
c) Calculate the radius of the loop so that the blocks just barely make it
d) Calculate the normal force acting on the blocks when they reach the bottom after traveling through the loop
Physics
1 answer:
Mars2501 [29]3 years ago
3 0
The correct answer is a I hope that helped enjoy the rest of your weekend
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Answer:

Im gonna say it is answer A:) Hope this helps!

Explanation:

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Light from a fluorescent lamp is observed through a cloud of cool nitrogen gas. Again, two students are having a discussion abou
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Answer:

From the previous explanation Student No. 1 has the correct explanation

Explanation:

When the fluorescent lamp emits a light it has the shape of its emission spectrum, this light collides with the atoms of Nitrogen and excites it, so these wavelengths disappear, lacking in the spectrum seen by the observed, for which we would see an absorption spectrum

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From the previous explanation Student No. 1 has the correct explanation

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3 years ago
A string of mass 60.0 g and length 2.0 m is fixed at both ends and with 500 N in tension. a. If a wave is sent along this string
Darya [45]

Answer:

a

The  speed of  wave is   v_1  = 129.1 \ m/s

b

The new speed of the two waves is v =  129.1 \ m/s

Explanation:

From the question we are told that

    The mass of the string is  m  =  60 \ g  =  60 *10^{-3} \ kg

    The length is  l  =  2.0 \ m

    The tension is  T  = 500 \ N

Now the velocity of the first wave is mathematically represented as

     v_1  = \sqrt{ \frac{T}{\mu} }

Where  \mu is the linear density which is mathematically represented as

      \mu  =  \frac{m}{l}

substituting values    

     \mu  =  \frac{ 60 *10^{-3}}{2.0 }

     \mu  =  0.03\ kg/m

So

   v_1  = \sqrt{ \frac{500}{0.03} }

   v_1  = 129.1 \ m/s

Now given that the Tension, mass and length are constant the velocity of the second wave will same as that of first wave (reference PHYS 1100 )

     

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Which type of friction occurs when an eraser is rubbed across a sheet of paper
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An eraser, a type of rubber, uses static friction when rubbed across a sheet of paper.
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