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3 years ago

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Objects 1 and 2 attract each other with a gravitational force of 72.0 units. If the distance separating Objects 1 and 2 is chang

ed to one-third the original value, then the new gravitational force will be units

1 answer:

gizmo_the_mogwai [7]3 years ago

3 0

Answer:

It is 24

Explanation:

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Pls what is a friendly relationship

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Answer:

A relationship where both members are freindly and supportive towards each other.

Explanation:

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4 years ago

Read 2 more answers

Use the impulse-momentum theorem to find how long a stone falling straight down takes to increase its speed from 5.6 m/s to 10.6

Nezavi [6.7K]

As stated, the impulse and momentum definitions will be used to later find the value of time through the force of gravity. According to the theory, the impulse formula is given as,

$I = F\Delta t$

Here,

F = Force

$\Delta t =$ Change in time

Now using the impulse theorem we have that,

Change in Impulse = Change in momentum

$F\Delta t = \Delta p$ (1)

The change in momentum is given as

$\Delta p = p_f -p_i$

$\Delta p = (-10.6)-(-5.6)$

$\Delta p = -5m/s$

The force due to gravity is through the Newton's second law

$F_g = -mg$

Here,

m = mass

g = Acceleration due to gravity

Substitute the value in (1)

$-mgt = -5m/s$

$9.8t = 4.9$

$t = \frac{5}{9.8}$

$t = 0.51s$

Therefore it will take 0.51s.

7 0

3 years ago

3. Order the following lengths from shortest to longest.

horrorfan [7]

Answer: $d < a < c < b$

$3.3 cm < 400 mm < 170 m < 22 km$

Explanation:

Firstly, let's convert these length to meters $m$ , in order to work with the same units:

a. 400 millimeters

$400 mm \frac{1m}{1000 mm}=0.4 m$

b. 22 kilometers

$22 km \frac{1000m}{1 km}=22000 m$

c. 170 meters

Here the lenght is already in meters

d. 3.3 centimeters

$3.3 cm \frac{1m}{100 cm}=0.033 m$

Now that we have all the lengths in meters, we can order them from shortest to longest:

$0.033 m < 0.4 m < 170 m < 22000 m$

or

$d < a < c < b$

7 0

4 years ago

Which of the following statements is FALSE about collisions? (Consider Newton's Laws an the Conservation of Momentum.)

pantera1 [17]

<u>The following statements are false about collisions: </u>

The velocity change of two respective objects involved in a collision will always be equal.
Total momentum is always conserved between any two objects involved in a collision.

Answer: Option B, and D

<u>Explanation: </u>

In any collisions, equal amount of net force will be acted upon the colliding objects due to the third law of Newton, irrespective of the significance difference in mass of the objects. Similarly, they can also have different acceleration values during collision of two objects if the masses are identical.

But the statements regarding the equal change in velocity of two objects respectively involved in collision always is false, as the conservation of momentum is applicable for isolated system only. So it is true for only isolated system and not in all the systems.

The same reason goes for falsifying the fourth statement which states that total momentum is always conserved between two objects involved in a collision as this statement is only true for isolated system where the conservation of momentum can be applied. Thus the second and fourth statement is false regarding collision.

8 0

3 years ago

A 50-cm-long spring is suspended from the ceiling. A 270 g mass is connected to the end and held at rest with the spring unstret

AveGali [126]

Answer:

k = 22.05 N/m

Explanation:

The potential energy of the mass is converted into potential energy of the spring.

Given:

mass m = 0.27 kg

gravitational constant g = 9.8 m/s²

distance falling/ stretching of spring h = 0.24 m

$U_{gravity} = U_{spring}\\ mgh = \frac{1}{2} kh^{2}$

Solving for k:

$k = 2mg\frac{1}{h}$

5 0

4 years ago