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kipiarov [429]
3 years ago
15

How to factor z^12 - 64 (question 17.)

Mathematics
1 answer:
aivan3 [116]3 years ago
4 0
(z^6 - 8)(z^6 + 8) is the answer. If you verify this by multiplying, you will see that: (z^6 - 8)(z^6 + 8) = z^(6+6) + 8z^6 - 8z^6 - 64 = z^12 + 0 - 64 = z^12 - 64 Hope this helps, Brian
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