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3 years ago

Y’all plz help fast

Mathematics

1 answer:

Wewaii [24]3 years ago

8 0

Can you comment the full question

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What is 0.9 as a fraction in simplest form

Brums [2.3K]

9/10 is the answer. Basic elementary math

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2 years ago

Read 2 more answers

Find the measure of each exterior angle.

devlian [24]

Answer:

The answer is 137 degrees

Step-by-step explanation:

Add up the two angles you know already

93 + 44 = 137

Then you take that number and subtract it from 180 in order to find the other interior angle.

180 - 137 = 43

So angle LKJ is 43 degree

Now to find the exterior angle you take the missing angles measurement

Which is 43 and subtract it from 180 to get 137

7 0

2 years ago

Which of the following polynomials is the expansion of (x - y)4? x4 - x3y + x2y2 - 2xy3 + y4 x4 -2x3y3 + y4 x4 - 2x3y + x 2y 2 -

sammy [17]

Answer:

$(x-y)^4=x^4-x^3y+6x^2y^2-4xy^3+y^4$ .

Step-by-step explanation:

We want to find the polynomial that will result from expanding:

$(x-y)^4$ .

Recall that we can use the Pascal's triangle to obtain the coefficient as:

1 4 6 4 1

Also note how the negative sign is going to alternate.

The power of x will decrease from left to right while the power of y increases from left to right

The expansion then becomes:

$(x-y)^4=x^4-x^3y+6x^2y^2-4xy^3+y^4$ .

7 0

2 years ago

A group of 22 students participated in a Race. Their scores are below

malfutka [58]

Answer:

idk bc it doesnt show

Step-by-step explanation:

put the answer in!!

8 0

2 years ago

Let f(x) = 9x3+ 21x2^ - 14 and g(x) = 3x + 1. Find " f (x) over g (x)

kondor19780726 [428]

Answer:

$\frac{f(x)}{g(x)}=3x^2+6x-2-\frac{12}{3x+1}$

Step-by-step explanation:

The first function is $f(x)=9x^3+21x^2-14$

The second function is $g(x)=3x+1$ .

$\frac{f(x)}{g(x)}=\frac{9x^3+21x^2-14}{3x+1}$

We perform the long division as shown in the attachment to obtain the quotient as: $Q(x)=3x^2+6x-2$ and remainder $R=-12$ .

Therefore:

$\frac{f(x)}{g(x)}=3x^2+6x-2-\frac{12}{3x+1}$

where $x\ne -\frac{1}{3}$

7 0

3 years ago