To graph a situation that would involve a linear graph, first determine your x and y axes.
The x-axis will be the independent variable, one that does not change based on other variables. An example is time.
The y-axis, the dependent variable, depends on the independent variable.
The model equation for a linear line is y = mx + b.
"m" is the slope, and the "b" is the y-intercept (where the graph crosses the x-axis at x=0).
For example, a situtation could be that Joe starts with $10 in his account and adds $5 every day to his account.
The x-axis is time in days.
The y-axis is amount of money in his account.
The slope, or rate of change is 5.
The y-intercept, the amount of money he has at x=0 (0 days) is $10.
The equation would be y = 5x + 10
To draw this, plot the y-intercept at (0, 10), and the next point would be 5 units up and one unit to the right because the slope is 5, or 5/1 (remember slope is rise over run: "rise" up 5 and "over" to the right 1).
I think it may be 3. not sure though
Answer: (4, -2)
<u>Step-by-step explanation:</u>
Inverse is when you swap the x's and y's: (-2, 4) --> (4, -2)
The predicted value of the car in the year 2006 to the nearest dollar would be $651.
<h3>What is the predicted value of the car?</h3>
The first step is to determine the rate of depreciation
g = (FV/PV)^(1/n) - 1
Where:
FV = value of the car in 2001
PV = value of the car in 1993
n = number ofyears = 8
(2700/26,300)^(1/8) - 1 = -24.76%
Now determine the value of the car in 2006
2700x ( 1 - 0.2476)^5 = $651
To learn more about depreciation, please check: brainly.com/question/25552427
