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Lisa [10]
3 years ago
5

5x (-2w-4) I need this asap

Mathematics
1 answer:
ira [324]3 years ago
4 0

Hello from MrBillDoesMath!

Answer:

-10w - 20


Discussion:

5 ( -2w - 4 )   =                    

5(-2w) - 5(4) =

-10w - 20

Thank you,

MrB

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At a factory that produces pistons for cars, Machine 1 produced 174 satisfactory pistons and 116 unsatisfactory pistons today. M
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Answer:

0.7 is the probability that the piston chosen from Machine 1 is satisfactory and the piston chosen from Machine 2 is unsatisfactory

Step-by-step explanation:

The two events are independent of each other.

Hence the probability of choosing satisfactory piston from Machine 1 and unsatisfactory piston from Machine 2 is equal  probability of choosing satisfactory piston from Machine 1 + probability of choosing unsatisfactory piston from Machine 2

Substituting the given values we get

Probability of choosing satisfactory piston from Machine 1 and unsatisfactory piston from Machine 2 =\frac{174}{174 +116} + \frac{20}{180 +20}

=\frac{174}{174 +116} + \frac{20}{180 +20}

== \frac{174}{290} + \frac{20}{200}\\= 0.6 + 0.1\\= 0.7

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<h3>Answer is  0</h3>

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Explanation:

Logarithms are used to solve exponential equations. Specifically if you have a variable in the exponent, then you use a log to isolate the variable.

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Or put another way,

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\bf \begin{cases} a\\\\ b \end{cases}\qquad \qquad \begin{array}{llll} \stackrel{\textit{the sum of \underline{a} and \underline{b}}}{a+b=33}\\\\ \stackrel{\textit{the sum of 7 times \underline{a} and 5 times \underline{b}}}{7a+5b=197} \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ a+b=33\implies \boxed{b}=33-a \\\\\\ \stackrel{\textit{substituting \boxed{b} in the second equation}}{7a+5\left(\boxed{33-a} \right)=197}\implies 7a+165-5a=197


\bf 2a+165=197\implies 2a=32\implies a=\cfrac{32}{2}\implies \blacktriangleright a=16 \blacktriangleleft \\\\\\ \boxed{b}=33-a\implies b=33-16\implies \blacktriangleright 17\blacktriangleleft

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