Answer:
P(B|A)=0.25 , P(A|B) =0.5
Step-by-step explanation:
The question provides the following data:
P(A)= 0.8
P(B)= 0.4
P(A∩B) = 0.2
Since the question does not mention which of the conditional probabilities need to be found out, I will show the working to calculate both of them.
To calculate the probability that event B will occur given that A has already occurred (P(B|A) is read as the probability of event B given A) can be calculated as:
P(B|A) = P(A∩B)/P(A)
= (0.2) / (0.8)
P(B|A)=0.25
To calculate the probability that event A will occur given that B has already occurred (P(A|B) is read as the probability of event A given B) can be calculated as:
P(A|B) = P(A∩B)/P(B)
= (0.2)/(0.4)
P(A|B) =0.5
I got a hold on hood for the
No
Given 3 sides of a triangle, the sum of any 2 sides must be greater than the third side.
Consider the 3 given sides 1, 7 and 11
7 + 11 = 18 > 1
1 + 11 = 12 > 7
1 + 7 < 11 ⇒ not valid
Hence these sides do not form a triangle
Hey there!
The key word in there is Many more. Whenever you see that word, it usually means to subtract
So you would subtract 4.5 from 8.1
8.1
-4.5= 3.6
