Question

Write as a monomial in standard form (-xy^4b^2)^4

Answer 1

Answer:

$\large\boxed{(-xy^4b^2)^4=x^4y^{16}b^8}$

Step-by-step explanation:

$(-xy^4b^2)^4\qquad\text{use}\ (ab)^n=a^nb^n\ \text{and}\ (a^n)^m=a^{nm}\\\\=(-1)^4(x)^4(y^4)^4(b^2)^4=1x^4y^{(4)(4)}b^{(2)(4)}=x^4y^{16}b^8$

Answer 2

Answer:

b^8x^4y^16.

Step-by-step explanation:

(-xy^4b^2)^4

= x^4 y^(4*4) b^(2*4)

= x^4y^16b^8

= b^8x^4y^16.