-4x + 6y = 12
x + 2y = -10
First solve for x in the second equation
x + 2y = -10
x = -10 - 2y
Now we have a value for x so we can substitute it into the other equation
-4 (-10 - 2y) + 6y = 12
Now solve for y
40 + 8y + 6y = 12
40 + 14y = 12
14y = -28
y = -2
Now we have a value for y that we can plug into one of the original equations so we can solve for x
x + 2y = -10
x + 2(-2) = -10
x - 4 = -10
x = -6
Your solution set is
(-6, -2)
Prime factorization of 160 = 2 x 2 x 2 x 2 x 2 x 5
Answer:
That is;
{25,45,65}
Step-by-step explanation:
Here, we want to find the set of A n B
That is the set that contains values that are present in both sets A and B
Mathematically, that will be;
{25,45,65}
It’ equals h=/y8x ok that is simple
Answer:
b > -5 3/8
Step-by-step explanation:
b+ 3 1/4 > -2 1/8
Subtract 3 1/4 from each side
b+ 3 1/4 - 3 1/4> -2 1/8- 3 1/4
b > -2 1/8- 3 1/4
Get a common denominator
3 1/4 *2/2 = 3 2/8
b > -2 1/8 - 3 2/8
b > -5 3/8
