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Salsk061 [2.6K]
4 years ago
11

Which number completes the square? x^2-4x?

Mathematics
1 answer:
ruslelena [56]4 years ago
4 0
X^2-4x=0 Let x=0 0^2=4(0)=0 0=0 [checks out] and x^2-4x=0 (4)^2-4(4)x=0 16-16=0 0=0 [also checks out]
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Bobby bought 3 5/12 ft of red ribbon and 5 1/12 ft of yellow ribbon.
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The answer is B) $10.20

8  \frac{6}{12} \:   is \: same \: as  \: \: 8 \frac{1}{2}

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3 years ago
If each time a student gets a good grade they get points but every bad point can
Olin [163]

Answer:

They get 4 good points!

Step-by-step explanation:

21-17= 4:)

6 0
3 years ago
Match the function in the left column with its period in the right column.
kiruha [24]

The results for the matching between function and its period are:

  • Option 1 - Letter D
  • Option 2 - Letter A
  • Option 3 - Letter C
  • Option 4 - Letter B

<h3>What is a Period of a Function?</h3>

If a given function presents repetitions, you can define the period as the smallest part of this repetition. As an example of periodic functions, you have: sin(x) and cos(x).

\mathrm{Period\:of\:}a\cdot \cos \left(bx\:+\:c\right)\:+\:d=\frac{\mathrm{periodicity\:of}\:\cos \left(x\right)}{|b|}

\mathrm{Period\:of\:}a\cdot \sin \left(bx\:+\:c\right)\:+\:d=\frac{\mathrm{periodicity\:of}\:\sin \left(x\right)}{|b|}

The period of sin(x) and cos(x) is 2π.

For solving this question, you should analyze each option to find its period.

1) Option 1

\mathrm{Periodicity\:of\:}a\cdot \cos \left(bx\:+\:c\right)\:+\:d=\frac{\mathrm{periodicity\:of}\:\cos \left(x\right)}{|b|}\\ \\ \mathrm{Periodicity\:of\:}a\cdot \cos \left(bx\:+\:c\right)\:+\:d=\frac{2\pi }{\frac{1}{2} }=4\pi

Thus, the option 1 matches with the letter D.

2) Option 2

\mathrm{Period\:of\:}a\cdot \sin \left(bx\:+\:c\right)\:+\:d=\frac{\mathrm{periodicity\:of}\:\sin \left(x\right)}{|b|}\\ \\ \mathrm{Period\:of\:}a\cdot \sin \left(bx\:+\:c\right)\:+\:d=\frac{2\pi}{4} =\frac{\pi }{2}

Thus, the option 2 matches with the letter A.

3) Option 3

\mathrm{Periodicity\:of\:}a\cdot \cos \left(bx\:+\:c\right)\:+\:d=\frac{\mathrm{periodicity\:of}\:\cos \left(x\right)}{|b|}\\ \\ \mathrm{Periodicity\:of\:}a\cdot \cos \left(bx\:+\:c\right)\:+\:d=\frac{2\pi}{2} =\pi

Thus, the option 3 matches with the letter C.

4) Option 4

\mathrm{Period\:of\:}a\cdot \sin \left(bx\:+\:c\right)\:+\:d=\frac{\mathrm{periodicity\:of}\:\sin \left(x\right)}{|b|}\\ \\ \mathrm{Period\:of\:}a\cdot \sin \left(bx\:+\:c\right)\:+\:d=\frac{2\pi}{8} =\frac{\pi }{4}

Thus, the option 4 matches with the letter B.

Read more about the period of a trigonometric function here:

brainly.com/question/9718162

#SPJ1

6 0
2 years ago
Can someone pls pls pls help me Evaluate the expression 6.908 – g for g = 0.173.
Serjik [45]

Answer:

6.735

Step-by-step explanation:

im smart

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3 years ago
EXPLAIN YOUR WORK PLZ
trasher [3.6K]

Answer:

D

Step-by-step explanation:

It will be $1,108.0 Because if you devide 40 by the hours, Plus the pay which is 15.40 You will get D

4 0
3 years ago
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