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AleksAgata [21]
3 years ago
10

An object is launched at 25 m/s from a height of 80 m. The equation for the height (h) in terms of time (t) is given by h(t)= -4

.9t^2 + 25t + 80. What is the objects maximum height?
Mathematics
1 answer:
Reptile [31]3 years ago
5 0
Use the formula for finding axis of symmetry:


        -b           -25         -25         
x = ------  ⇒ --------- = -------- = 2.6 
       2a         2(-4.9)     -9.8



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Step-by-step explanation:

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Step-by-step explanation:

Given:

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So Area = length * width
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Now.. this is obviously wrong.. they want us to find the correct length..
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