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AleksAgata
[21]
4 years ago
10
An object is launched at 25 m/s from a height of 80 m. The equation for the height (h) in terms of time (t) is given by h(t)= -4
.9t^2 + 25t + 80. What is the objects maximum height?
Mathematics
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1
answer:
Reptile
[31]
4 years ago
5
0
Use the formula for finding axis of symmetry:
-b -25 -25
x = ------ ⇒ --------- = -------- = 2.6
2a 2(-4.9) -9.8
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