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Blizzard [7]
2 years ago
12

For the following right triangle find the side length x

Mathematics
1 answer:
lbvjy [14]2 years ago
3 0
78’ degrees on the right side
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Any actives ???can y’all please help me
kkurt [141]

Answer:

B: $2.50

Step-by-step explanation:

Step 1: form an equation

126 = 12(8 + x)

Step 2: isolate the x

126/12 = 8 + x

126/12 - 8 = x

Step 3: solve

10.5 - 8 = x

2.5 = x = raise per hour

7 0
2 years ago
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How do you do these two questions?
Mice21 [21]

Answer:

a) d²y/dx² = ½ x + y − ½

b) Relative minimum

Step-by-step explanation:

a) Take the derivative with respect to x.

dy/dx = ½ x + y − 1

d²y/dx² = ½ + dy/dx

d²y/dx² = ½ + (½ x + y − 1)

d²y/dx² = ½ x + y − ½

b) At (0, 1), the first and second derivatives are:

dy/dx = ½ (0) + (1) − 1

dy/dx = 0

d²y/dx² = ½ (0) + (1) − ½

d²y/dx² = ½

The first derivative is 0, and the second derivative is positive (concave up).  Therefore, the point is a relative minimum.

4 0
3 years ago
30 points !!!!!!!!Solve the following problem. Show ALL steps to receive full credit.
Aleksandr [31]
7x - 8 = 8 + 3x
7x - 3x = 8 + 8
4x = 16
x = 16/4
x = 4
5 0
3 years ago
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determine if you can use the HL congruence theorem to prove the triangles congruent. if not, tell what else you need to know
kherson [118]
I need an actual picture to solve this
4 0
3 years ago
Use the diagram to determine which statement is true
hichkok12 [17]
A. Area of ABCD - Area of DGA = Area of DEFG
s^2 - 1/2bh = s^2
(5)^2 - 1/2(4)(3) = (3)^2
25 - 1/2(12) = 9
25 - 24 = 9
1 not equal to 9

B. Area of ABCD - Area of GHIA = Area of DGA
s^2 - s^2 = 1/2bh
(5)^2 - (4)^2 = 1/2(4)(3)
25 - 16 = 1/2(12)
9 not equal to 6

C. Area of ABCD + Area of DGA = Area of GHIA
s^2 + 1/2bh = s^2
(5)^2 + 1/2(4)(3) = (4)^2
25 + 1/2(12) = 16
25 + 6 = 16
31 not equal to 16

D. Area of DEFG + Area of GHIA = Area of ABCD
s^2 + s^2 = s^2
(3)^2 + (4)^2 = (5)^2
9 + 16 = 25
25 = 25

The answer is D.
5 0
3 years ago
Read 2 more answers
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