<span>let n+2=u
so, the equation became= [2/u]-[3/u]=5
=> [(2+3)/u]=5
=> 5/u=5
=> u=5/5=1
thus, u=1
we know u=n+2
so, n+2=1
=> n=1-2=-1
so, n=-1</span>
Answer:
d-2 and d cannot = 8
Step-by-step explanation:
d^2 -10d+16
-----------------------
d-8
Factor the numerator
( d-8)(d-2)
-------------------
d-8
The undefined values occur when the denominator is equal to zero
d-8 = 0
d= 8
This means d cannot equal 8
Now cancel like terms in the equation ( d-8)
This yields d-2
Yes I agree with that because you combined the terms in the monomial correctly and the degree of the monomial was greater then the degree of any other mono/binomials in the polynomial
I don’t think so because I’m pretty sure you can not square a negative, the fraction is kinda throwing me off
Answer:40.00212258
Step-by-step explanation:
(4 x 75384) ➗ 7538
301536 ➗ 7538=40.00212258