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Luda [366]
3 years ago
14

PlEASE HELP ME AND I WILL GiVE U BRAINLIEST

Mathematics
1 answer:
Ghella [55]3 years ago
6 0

Answer:

-1!

Step-by-step explanation:

If you plot the points on a graph, use RISE/RUN! You will see that you go up 5, left 5. Since you went left, it's a negative slope. 5/5 is 1, so the answer is -1! I really hope this makes sense, but if you need help, Im here!

I included a graph if you need to see it!

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The area is 7, the width is 2 2/9 what is the length?
alexandr402 [8]
3.15 is the answerrrrrrrr
4 0
3 years ago
Write each ratio in simplest form.1.1.4/7
horsena [70]
1.4 / 7

multiply by 10 in both up and down
(1.4*10) / (7*10)
14 / 70

divide by 7
(14/7) / (70/7)
2 / 10

divide by 2
(2/2) / (10/2)
1 / 5
3 0
3 years ago
Find the values of the 30th and 90th percentiles of the data. Please show your work.
MaRussiya [10]

Answer:

30th percentile:109

90th percentile: 188

Step-by-step explanation:

The given data set is:

129, 113, 200, 100, 105, 132, 100, 176, 146, 152

We arrange the data set in ascending order to obtain;

Array= 100,100,105,113,129,132,146,176,200

The 30th percentile is located at

(\frac{30}{100}\times 10 )} -th position, where n=10 is the number of items in the data set

This implies that the 30th percentile is at the 3rd position.

Since 3 is an integer, the 30th percentile is the average of the 3rd and 4th occurrence in the array;

This implies that the 30th percentile = \frac{105+113}{2}=\frac{218}{2}=109

The 90th percentile is located at

(\frac{90}{100}\times 10 )} -th position, where n=10 is the number of items in the data set

This implies that the 90th percentile is at the 9th position.

Since 9 is an integer, the 90th percentile is the average of the 9th and 10th occurrence in the array;

This implies that the 90th percentile = \frac{176+200}{2}=\frac{376}{2}=188

6 0
3 years ago
Write the first six terms of the geometric sequence with the first term 6 and common ratio 1/3
Alja [10]

Answer:

6, 2, 2/3, 2/9, 2/27, 2/81

Step-by-step explanation:

The nth term of a geometric progression is expressed as;

Tn  = ar^n-1

a is the first term

n is the number of terms

r is the common ratio

Given

a = 6

r = 1/3

when n = 1

T1 = 6(1/3)^1-1

T1 = 6(1/3)^0

T1 = 6

when n = 2

T2= 6(1/3)^2-1

T2= 6(1/3)^1

T2 = 2

when n = 3

T3 = 6(1/3)^3-1

T3= 6(1/3)^2

T3= 6 * 1/9

T3 = 2/3

when n = 4

T4 = 6(1/3)^4-1

T4= 6(1/3)^3

T4= 6 * 1/27

T4 = 2/9

when n = 5

T5 = 6(1/3)^5-1

T5= 6(1/3)^4

T5= 6 * 1/81

T5 = 2/27

when n = 6

T6 = 6(1/3)^6-1

T6= 6(1/3)^5

T6= 6 * 1/243

T6 = 2/81

Hence the first six terms are 6, 2, 2/3, 2/9, 2/27, 2/81

6 0
3 years ago
which descriptions from the list below describe the relationship between xyz and uvw check all that apply
Cloud [144]

Answer:

similar and same shape.

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
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