Question

What is an important step to determine the number of grams of SO3 that can be produced by reacting 6 moles of SO2 with oxygen in the synthesis reaction below. 2 SO2(g) + O2(g) —>2 SO3(g)

Answer 1

Answer:

480.40 g.

Explanation:

• According to the balanced equation:

2 SO₂(g) + O₂(g) → 2 SO₃(g),

it is clear that 2.0 moles of SO₂ react with 1.0 mole of oxygen to produce 2.0 moles of SO₃.

• We can get the no. of moles of SO₃ produced:

∵ 2.0 moles of SO₂ produce → 2.0 moles of SO₃, from the stichiometry.

∴ 6.0 moles of SO₂ produce → 6.0 moles of SO₃.

• Then, we can get the mass of the produced 6.0 moles of SO₃ using the relation:

mass =  no. of moles x molar mass of SO₃ = (6.0 moles)(80.066 g/mol) = 480.396 g ≅ 480.40 g.