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Svetradugi [14.3K]
2 years ago
8

What is an important step to determine the number of grams of SO3 that can be produced by reacting 6 moles of SO2 with oxygen in

the synthesis reaction below. 2 SO2(g) + O2(g) —>2 SO3(g)
Chemistry
1 answer:
vagabundo [1.1K]2 years ago
3 0

Answer:

480.40 g.

Explanation:

  • According to the balanced equation:

<em>2 SO₂(g) + O₂(g) → 2 SO₃(g),</em>

it is clear that 2.0 moles of SO₂ react with 1.0 mole of oxygen to produce 2.0 moles of SO₃.

  • We can get the no. of moles of SO₃ produced:

∵ 2.0 moles of SO₂ produce → 2.0 moles of SO₃, from the stichiometry.

∴ 6.0 moles of SO₂ produce → 6.0 moles of SO₃.

  • Then, we can get the mass of the produced 6.0 moles of SO₃ using the relation:

<em>mass =  no. of moles x molar mass of SO₃</em> = (6.0 moles)(80.066 g/mol) = <em>480.396 g ≅ 480.40 g.</em>

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T

P

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c

o

n

s

t

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N

A

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