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UkoKoshka [18]
3 years ago
15

Which of these is made up of cells and tissues that perform a larger function? Group of answer choices Atom Compound Molecule Or

gan
Chemistry
2 answers:
Anit [1.1K]3 years ago
5 0

Answer:

compound

Explanation:

because it is made up of pure substance consists of atom

MrMuchimi3 years ago
3 0

Answer:

Organ

Explanation:

I got it right when I took the test.

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Find the mass of an object that has a density of 1.5 g/cm3 and has a volume of 8cm3
zubka84 [21]

Answer:

density= 1.5 g/cm3

volume= 8cm 3

mass = density×volume

mass= 1.5×8

= 12 g

7 0
3 years ago
HELP
Jobisdone [24]

Answer:

hello,

first one is 25.15

second is 301.55

Explanation:

honestly if you look up on the internet there is a converter to get you your answers

5 0
3 years ago
Read 2 more answers
What is the velosity of a 72.3 kg jogger with a kinetic energy of 1080.0 J?
Svet_ta [14]

Answer: 5.47m/s

Explanation:

Mass = 72.3kg

K.E = 1080.0J

V =?

K.E = 1 /2MV^2

V^2 = 2K.E /M = (2x1080)/72.3

V = sqrt [(2x1080)/72.3]

V = 5.47m/s

7 0
3 years ago
You wish to prepare an HC2H3O2 buffer with a pH of 4.24. If the pKa of is 4.74, what ratio of C2H3O2 /HC2H3O2 must you use?
LenaWriter [7]

To solve this problem, we can use the Henderson-Hasselbalch Equation which relates the pH to the measure of acidity pKa. The equation is given as:<span>

<span>pH = pKa + log ([base]/[acid])                ---> 1</span></span>

Where,

[base] = concentration of C2H3O2 in molarity or moles

<span>[acid] = concentration of  HC2H3O2 in molarity or moles</span>

 

For the sake of easy calculation, let us assume that:

[base] = 1

[acid] = x

<span>
Therefore using equation 1,
4.24 = 4.74 + log (1 / x) 

<span>log (1 / x) = - 0.5

1 / x = 0.6065 </span></span>

x = 1.65<span>

The required ratio of C2H3O2 /HC2H3O2 <span>is 1:1.65 or 3:5. </span></span>
3 0
3 years ago
_______ prohibits and punishes certain conduct for the benefit of society.
Dmitrij [34]

Answer:

animal

Explanation:

follow and make brainliest

5 0
3 years ago
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