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Bumek [7]
3 years ago
8

You have recovered two LacZ-minus AmpR colonies from your transformation in Lab 7 and they appear as white colonies on a LBAX pl

ate. You test each colony on a LBT plate. Only one of these two colonies grew on the LBT plate (Colony 1) while the other colony did not grow on the LBT plate (Colony 2). What is most likely the plasmid contained in Colony 2?
A: pUC119
B: pACYC184
C: pUC-tet(resistant)
D: pUC-chloramphenicol(minus)
Chemistry
1 answer:
svlad2 [7]3 years ago
7 0

Answer:

D. pUC-chloramphenicol(minus)

Explanation:

It contains chloramphenicol resistance gen, the PMB1 posses origin of replication (ori), beta-galactosidase coding gen Laz. It also has pUC18 with many cloning site in the Lac Z gene which makes the recombinant clones to be verified via culture plates which is made up of IPTG and X- Gal.

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What is the farthest distance the moon gets from Earth?
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When the Moon is the farthest away, it's 252,088 miles away. That's almost 32 Earths.

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4 0
3 years ago
Read 2 more answers
Describe how you could use two LB/agar plates, some E. coli, and some ampicillin to determine how E. coli cells are affected by
KiRa [710]

Answer:

For this experiment we are going to take plate 1 as the control plate, so, in it there will be just E. coli in LB/agar; in plate 2, we are going to put E. coli in LB/agar and some ampicillin.  Then, we have to wait for the E. coli colonies to form. After a while, the E. coli growth can be compared on both plates and determine if ampicillin affects or not the E. coli colonies.

Explanation:

If the ampicillin affects negatively E. coli colonies, we are going to observe that in plate 1 (control plate) there are E. coli colonies growing, but in plate 2, there is no E. coli colonies or, at least, there is a fewer number of colonies on it. If ampicillin doesn't affect E.coli, plate 1 (control) and plate 2 (ampicillin experiment) are going to be similar in number of colonies.

8 0
3 years ago
All bases have a(n).<br> taste.
Zarrin [17]
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6 0
3 years ago
A 1,900-m3 water tower has been cleaned with a chlorine solution. The vapors of chlorine in the tower exceed allowable concentra
yaroslaw [1]

Answer:

t = 1862 s

Explanation:

To do this, we need first to determine the theorical detention time, which can be determined with the following expression:

t₀ = ∀/Q  (1)

Where:

t₀: detention time

∀: Volume of the fluid in the reactor

Q: Flow rate in the reactor

With this time, we must use the following expression to determine the time that the workers will take to vent the tank:

C = C₀ e^(-t/t₀)   (2)

From here, we must solve for time t, and the expression will be:

t = ln(C₀/C) * t₀   (3)

Now that we know the expression to use, let's solve for t. Using (1) to determine the detention time, ∀ is 1900 m³, and Q is 2.35 m³/s so:

t₀ = 1900 / 2.35 = 808.51 s

Now, let's solve for the time t. C will be 0.0015 mg/L (or 1.5 mg/m³ cause in 1 m³ we have 1000 L) and C₀ 15 mg/m³:

t = ln(15/1.5) * 808.51

<h2>t = 1861.66 s or simply 1862 s</h2><h2></h2>

Hope this helps

6 0
3 years ago
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