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Gre4nikov [31]
3 years ago
9

The amount of grazing land available for each cow varies inversely with the

Mathematics
1 answer:
Nookie1986 [14]3 years ago
6 0

Answer:

0.4 acres are available for 50 cows.

Step-by-step explanation:

As it is given that:

Number of cows is inversely proportional to amount of land.

[Inversely proportional means that when one quantity is increased, other is decreased respectively]

Now the scenario is:

    COWS                     ACRES

       10                            2

       50                           X

As they are inversely proportional so for finding X the equation will be:

10/50=X/2

(10/50)*2 =X

20/50 = X

0.4 = X

So there would be 0.4 acres available for each cow.

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What is the area of this triangle ?
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Answer:

Area of triangle is 9.88 units^2

Step-by-step explanation:

We need to find the area of triangle

Given E(5,1), F(0,4), D(0,8)

We will use formula:

Area\,\,of\,\,triangle =\sqrt{s(s-a)(s-b)s-c)} \\where\,\, s = \frac{a+b+c}{2}

We need to find the lengths of side DE, EF and FD

Length of side DE = a = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}

Length of side DE = a = =\sqrt{(5-0)^2+(1-8)^2}\\=\sqrt{(5)^2+(-7)^2}\\=\sqrt{25+49}\\=\sqrt{74}\\=8.60

Length of side EF = b = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}

Length of side EF = b = =\sqrt{(0-5)^2+(4-1)^2}\\=\sqrt{(-5)^2+(3)^2}\\=\sqrt{25+9}\\=\sqrt{34}\\=5.8

Length of side FD = c = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}

Length of side FD = c = =\sqrt{(0-0)^2+(8-4)^2}\\=\sqrt{(0)^2+(4)^2}\\=\sqrt{0+16}\\=\sqrt{16}\\=4

so, a= 8.60, b= 5.8 and c = 4

s = a+b+c/2

s= 8.6+5.8+4/2

s= 9.2

Area of triangle==\sqrt{s(s-a)(s-b)s-c)}\\=\sqrt{9.2(9.2-8.6)(9.2-5.8)(9.2-4)}\\=\sqrt{9.2(0.6)(3.4)(5.2)}\\=\sqrt{97.5936}\\=9.88

So, area of triangle is 9.88 units^2

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3 years ago
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Find cos(β) in the triangle.
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3 years ago
PLEASE HELP WILL MARK BRAINLIEST!!!!!
trapecia [35]

The numbers inside the parenthesis is the value of x, uses the equation associated with the value of x and solve.

H(1) Since 1 fits 1≤x≤3 use x^3

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