What are the 2 key parts of an exponential function
1 answer:
Answer:
<em>The a and the base value</em>
Step-by-step explanation:
<em>Depending on the number of the a or b value, the graph can be completely altered! In a standard exponential function, the b value is 2</em>
<em>An exponential function with both an a and a B value looks like this:</em>
<em> </em>
<em>The a value is the starting point of the exponential function. Not all function will have starting points, mind you! The a value can be negative or positive, which would affect the point which the graph of the exponential function starts.</em>
<em>The b value is like the 'rate of change' for the exponential function. It can also be positive or negative -- depending on the sign of the b value, the function can decrease of increase.</em>
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Answer:
Given that the equation of a circle is :
Answer:
Area of trapezium = 4.4132 R²
Step-by-step explanation:
Given, MNPK is a trapezoid
MN = PK and ∠NMK = 65°
OT = R.
⇒ ∠PKM = 65° and also ∠MNP = ∠KPN = x (say).
Now, sum of interior angles in a quadrilateral of 4 sides = 360°.
⇒ x + x + 65° + 65° = 360°
⇒ x = 115°.
Here, NS is a tangent to the circle and ∠NSO = 90°
consider triangle NOS;
line joining O and N bisects the angle ∠MNP
⇒ ∠ONS = = 57.5°
Now, tan(57.5°) =
⇒ 1.5697 =
⇒ SN = 0.637 R
⇒ NP = 2×SN = 2× 0.637 R = 1.274 R
Now, draw a line parallel to ST from N to line MK
let the intersection point be Q.
⇒ NQ = 2R
Consider triangle NQM,
tan(∠NMQ) =
⇒ tan65° =
⇒ QM =
QM = 0.9326 R .
⇒ MT = MQ + QT
= 0.9326 R + 0.637 R (as QT = SN)
⇒ MT = 1.5696 R
⇒ MK = 2×MT = 2×1.5696 R = 3.1392 R
Now, area of trapezium is (sum of parallel sides/ 2)×(distance between them).
⇒ A = () × (ST)
= () × 2 R
= 4.4132 R²
⇒ Area of trapezium = 4.4132 R²